Three capacitors of equal capacitance, when connected in series have net capacitance `C_(1)`, and when connected in parallel have net capacitance `C_(2)`. What is the value of `C_(1)//C_(2)`?

Two capacitors of equal capacitance when connected in series hae net capacitance C_(1) and when connected in parallel have net capacitance C_(2) what is the value of C_(1)//C_(2) ?

Five equal capacitors are connected in series and have net capacitance C_1 and when connected in parallel, they have capacitance C_2 . The value of C_1/C_2 :

Four capacitors of equal capacitance have an equivalent capacitance C_(1) when connected in series and an equivalent capacitance C_(2) when connected in parallel. The ratio (C_(1))/(C_(2)) is

n idential capacitors each of capacitance C when connected in series give equivalent capacitance 1.2muF and when connect in parallel give 120muF . Then n and C are

When two capacitances are connected in series, the equivalent capacitance is 2.4muF and when they connected in parallel, it is 10muF . The individual capacitances are

There are 7 identical capacitors. The equivalent capacitance when they are connected in series is C. The equivalent capacitance when they are connected in parallel is

Two capacitors have a capacitance of 5 muF when connected in parallel and 1.2 muF when connected in series. Calculate their capacitance.

Condensers of capacity 4muF , 5muF and 6muF are connected first in series . The effective capacitance is C_(1) . When they are connected in parallel, the effective capacitance is C_(2) . Then the ratio C_(2)//C_(1) will be

Three capacitors C_(a) t c_(b) lt C_(c) are connected in series. Their resultant capacitance will be