A cell of emf `1.1 V` and internal resistance `0.5 Omega` is connected to a wire of resistance `0.5 Omega`. Another cell of the same emf is connected in series bur the current in the wire remain the same .Find the internal resistance of second cell

A battery of emf 2V and internal resistance 0.5(Omega) is connected across a resistance in 1 second?

A battery having e.m.f. 5 V and internal resistance 0.5 Omega is connected with a resistance of 4.5 Omega then the voltage at the terminals of battery is

24 cells of emf 1.5 V each having internal resistance of 1 Omega are connected to an external resistance of 1.5Omega . To get maximum current,

A cell of emf 2 volt and internal resistance 1.5 Omega is connected to the ends of 1 m long wire. The resistance of wire is 0.5 Omega/m . Find the value of potential gradient on the wire.

A cell of emf 2 volt and internal resistance 1.5Omega is connected to the ends of 1 long wire. The resistance of wire is (0.5Omega)/(m) . Find the value of potential gradient on the wire.

An accumulator of emf 2 V and negligible internal resistance is connected across a uniform wire of length 10 m and resistance 30 Omega The appropriate terminals of a cell of emf 1.5 V and internal resistance 1 Omega is connected to one end of the wire and the other terminal of the cell is connected through a sensitive galvanometer to a slider on the wire. What is the length of the wire that will be required to produce zero deflection of the galvanometer? How will the balancing length change? (a) When a coil of resistance 5Omega is placed in series with the accumulator. (b) The cell of 1.5 V is shunted with 5 Omega resistor?