Acceleration due to gravity ' g ' for a body of mass ' m ' on earth's surface is proportional to (Radius of earth= R , mass of earth= M

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

The ratio of acceleration due to gravity at a height 3R above earth 's surface to the acceleration due to gravity on the surface of the earth is (where R=radius of earth)

The acceleration due to gravity on the surface of the earth is g. If a body of mass m is raised from the surface of the earth to a height equal to the radius R of the earth, then the gain in its potential energy is given by

What will be the acceleration due to gravity at height h lt lt R . Where R is radius of earth and g is acceleration to gravity on the surface earth

The acceleration due to gravity'g' for objects on or near the surface of earth is related to the universal gravitational constant 'G' as ('M' is the mass of the earth and 'R' is its radius):

The radius of the earth R and acceleration due to gravity at its surface is g . If a body of mass m is sent to a height of R//4 from the earth's surface, the potential energy increases by

The kinetic energy needed to project a body of mass m from the earth's surface to infinity is (R is radius of the earth, g is gravitational acceleration on the surface of the earth)