The position "x" of a particle varies with time (t) as x=At^(2)-Bt^(3)" .the acceleration at time t of the particle will be equal to zero

The position x of a particle varies with time t as x=at^(2)-bt^(3) .The acceleration of the particle will be zero at time t equal to

The position x of a particle varies with time t as X=at^(2)-bt^(3).The acceleration of the particle will be zero at time (t) equal to

The position x of a particle varies with time t as x=a t^(2)-b . For what value of t acceleration is zero?

The position x of a body is defined by equation x = Pt^(2)- Q t^(3) . The acceleration of the particle will be zero at time equal to

The position of a point in time t is given by x=a+bt-ct^(2),y=at+bt^(2) . Its acceleration at time t is

The position of a point in time t is given by x=a+bt-ct^(2),y=at+bt^(2) . Its acceleration at time t is

The displacement x of a particle varies with time t as x=4t^(2)-15t+25 Find the position, velocity and acceleration of the particle at t=0. When will the velocity of the particle become zero? Can we call the motion of the particle as one with uniform acceleration ?

the angular velocity omega of a particle varies with time t as omega = 5t^2 + 25 rad/s . the angular acceleration of the particle at t=1 s is