If mass of the earth is `M`, radius is `R`, and gravitational constant is `G`, then workdone to take `1kg` mass from earth surface to infinity will be

If mass of earth is M ,radius is R and gravitational constant is G,then work done to take 1kg mass from earth surface to infinity will be (A) sqrt((GM)/(2R)) (B) (GM)/(R)] (C) sqrt((2GM)/(R))]

If M be the mass of the earth, R its radius (assumed spherical) and G gravitational constant, then the amount of work that must be done on a body of mass m, so that it completely escapes from the gravity of the earth of the earth is given by

The escape velocity of an object from the earth depends upon the mass of the earth ( M ), its mean density (rho) , its radius ( R ) and the gravitational constant ( G ). Thus the formula for escape velocity is

Find the gravitational potential energy of a body of mass 200 kg on the earth's surface.

A particle of mass m is thrown upwards from the surface of the earth, with a velocity u . The mass and the radius of the earth are, respectively, M and R . G is gravitational constant g is acceleration due to gravity on the surface of earth. The minimum value of u so that the particle does not return back to earth is

The gravitational potential energy of a body of mass ‘ m ’ at the earth’s surface -mgR_(e) . Its gravitational potential energy at a height R_(e) from the earth’s surface will be (Here R_(e) is the radius of the earth)

The kinetic energy needed to project a body of mass m from the earth surface (radius R) to infinity is

If M is the mass of the earth and R its radius, the radio of the gravitational acceleration and the gravitational constant is

If M is the mass of the earth and R its radius, then ratio of the gravitational acceleration and the gravitational constant is

The gravitational potential energy of body of mass 'm' at the earth's surface mgR_(e) . Its gravitational potential energy at a height R_(e) fromt the earth's surface will be (here R_(e) is the radius of the earth)