If the intercepts on the coordinate axes are `8,4,4` for a plane,then what will be the length of the perpendicular from the origin on to the plane?

The length of the perpendicular from origin to the plane x-3y+4z=6 is

IF for a plane the intercepts on the coordinate axes are 8,4,4 then the length of the perpendicular from the origin on to the plane is (A) 8/3 (B) 3/8 (C) 3 (D) 4/3

What is the length of the perpendicular from the origin to the plane ax+by+sqrt(ab)z=1 ?

What is the length of the perpendicular from the origin to the plane ax+by+sqrt(2abz)=1 ?

If a plane, intercepts on the coordinates axes at 8,4,4 then the length of the perpendicular from the origin to the plane is

The length of the perpendicular from the origin to the plane 3x + 4y + 12 z =52 is

Find the coordinates of the foot of the perpendicular drawn from the origin to the plane 3y+4z-6=0 .