If mass of earth is M ,radius is R and gravitational constant is G,then work done to take 1kg mass from earth surface to infinity will be (A) sqrt((GM)/(2R)) (B) (GM)/(R)] (C) sqrt((2GM)/(R))]

If mass of the earth is M , radius is R , and gravitational constant is G , then workdone to take 1kg mass from earth surface to infinity will be

v_(e)=sqrt((2GM)/(R))

The work done to take a particle of mass m from surface of the earth to a height equal to 2R is

The kinetic energy needed to project a body of mass m from the earth surface (radius R) to infinity is

If M is the mass of the earth and R its radius, the radio of the gravitational acceleration and the gravitational constant is

If M be the mass of the earth, R its radius (assumed spherical) and G gravitational constant, then the amount of work that must be done on a body of mass m, so that it completely escapes from the gravity of the earth of the earth is given by

The intensity of gravitational field at the centre of a ring of mass m and radius R is (A) Zero (B)(Gm)/(2r^(2) (C) "(Gm)/(r^(2) (D) (2Gm)/(r^(2)

If M is the mass of the earth and R its radius, then ratio of the gravitational acceleration and the gravitational constant is

A satellite of earth of mass 'm' is taken from orbital radius 2R to 3R, then minimum work done is :-

A body of mass 100 gm is rotating on a circular path of radius r with constant velocity . The work done in one complete revolution will be :