The equation of the curve for which the slope of the tangent at any point is given by `(x+y+1)((dy)/(dx))=1` is (where, c is an arbitrary constant)

The point on the curve y=2x^(2) , where the slope of the tangent is 8, is :

The solution of the differential equation x(dy)/(dx)=y ln ((y^(2))/(x^(2))) is (where, c is an arbitrary constant)

The solution of the differential equation (dy)/(dx)=(x-y)/(x-3y) is (where, c is an arbitrary constant)

The solution of the differential equation (dy)/(dx)=(2x-y)/(x-6y) is (where c is an arbitrary constant)

The equation of the curve lying in the first quadrant, such that the portion of the x - axis cut - off between the origin and the tangent at any point P is equal to the ordinate of P, is (where, c is an arbitrary constant)

The solution of differential equation x^(2)(x dy + y dx) = (xy - 1)^(2) dx is (where c is an arbitrary constant)

Find the equation of a curve, passes through (-2,3) at which the slope of tangent at any point (x,y) is (2x)/(y^(2)) .

The solution of the differential equation ycosx.dx=sinx.dy+xy^(2)dx is (where, c is an arbitrary constant)

The solution of the differential equation (dy)/(dx)+(y)/(x)=(1)/((1+lnx+lny)^(2)) is (where, c is an arbitrary constant)

The solution of the differential equation (1-x^(2))(dy)/(dx)-xy=1 is (where, |x|lt1, x in R and C is an arbitrary constant)