Find the product of two matrices A and B where `A=[[-5,1,3],[7,1,-5],[1,-1,1]]`, `B=[[1,1,2],[3,2,1],[2,1,3]]`,use it to solve system of linear equation x+y+2z=1,3x+2y+z=7,2x+y+3z=2`

Determine the product [[-4, 4, 4], [-7, 1, 3],[5, -3, -1]][[1, -1, 1],[1, -2, -2],[2, 1, 3]] and use it to solve the system of equations x – y + z = 4, x – 2y – 2z = 9, 2x + y + 3z = 1

If A=[[1,-1,12,1,-31,1,1]], find A^(-1) and hence solve the system of linear equation.x+2y+z=4,-x+y+z=0,x-3y+z=2

Use product [[1,-1, 2],[ 0, 2,-3],[ 3,-2, 4]] [[-2, 0, 1],[ 9, 2,-3],[ 6, 1,-2]] to solve the system of equation: x-y+2z=1; 2y-3z=1; 3x-2y+4z=2

Given A=[[1,-1, 0], [2, 3, 4], [0, 1, 2]], B= [[2,2,-4],[-4,2,-4],[2,-1,5]] find AB and use this to solve the system of equations: y+2x=7,x-y=3,2x+3y+4z=17

The solution of the system of equations is x-y+2z=1,2y-3z=1 and 3x-2y+4y=2 is

If A=[[1,3,4],[2,1,2],[5,1,1]] , find A^(-1) . Hence solve the system of equations : x+3y+4z=8, 2x+y+2z=5 and 5x+y+z=7

The equations x+2y+3z=1 2x+y+3z=1 5x+5y+9z=4

If matrix A=[[2,3,1],[1,2,2],[-3,1,-1]] Find A^(-1) and hence solve the system of equation 2x+y-3z=13,3x+2y+z=4,x+2y-z=8

Solve system of linear equations,using matrix method,2x+y+z=1x-2y-z=(3)/(2)3y-5z=9