If the vertices `A,B,C` of `/_ABC` are `(1,2,3),(-1,0,0),(0,1,2)` respectively then `cos^(2)B` is equal to

If the vertices A,B,C of a triangle ABC are (1,2,3),(-1,0,0) ,(0,1,2) , respectively, then find angleABC .

If the vectors A,B,C of a triangle ABC are (1,2,3),(-1,0,0),(0,1,2), respectively then find /_ABC.

If the position vectors of the vertices a, B and C of a Triangle ABC be (1, 2, 3), (-1, 0, 0) and (0, 1, 2) respectively then find angleABC .

If the vertices A, B, C of a triangle ABC are (1," "2," "3)," "(1," "0," "0)," "(0," "1," "2) , respectively, then find /_A B C . [/_A B C is the angle between the vectors vec( B A) and vec (B C) .

If {:A=[(1,0,0),(0,1,0),(a,b,-1)]:} , then A^2 is equal to

Find the equation of the side BC of the triangle ABC whose vertices A,B,C are (-1,-2),(0,1) and (2,0) respectively.Also find the equation of the median through (-1,-2) .

The vertices of a triangle ABC are A (1,-2, 2), B (1, 4, 0) and C (-4, 1, 1) respectively. If M be the foot of perpendicular drawn from B on AC, then vec BM is

The coordinates of the vertices B and C of a triangle ABC are (2,0) and (8,0), respectively.Vertex A is moving in such a way that 4tan(3)/(2)tan(C)/(2)=1. Then find the locus of A