In Region of Electric field Given by `vec(E)=(Ax-B)hat(I)`. Where `A=20` unit and `B=10` unit. If Electric potential at `x=1m` is `v_(2)`. Then `v_(1)-v_(2)` is equal to

The electric field in a region of space is given as bar(E)=(5xhat i-2hat j) .Potential at point x =1 y =1 is V_(1) and potential at point x =2 y =3 is V_(2) .Then V_(1)-V_(2) is equal to

The electric field in a region of space is given as bar(E)=(5xhat i-2hat j) .Potential at point x=1 y=1 is V_(1) and potential at point (x=2 y=3) is V_(2) .Then V_(1) -V_(2) is equal to

If the electric field is given by vec(E ) = ((100)/(x^(2)))i the potential difference between points x=10m and x=20m in volts is

An electric field is given by vec(E )=(yhat(i)+hat(j))NC^(-1) . Find the work done (in j) by the electric field in moving a 1 C charge form vecr_(A)=(2 hat(i)+2 hat(j))m to vecr_(B)=(4 hat(i)+hat(j))m .

In any region, if electric field is define as bar(E ) = ( hat(i) + 2 hat(j)+ hat(k))V//m , then the potential differnece between two points A ( 0,0,0) and B ( 2,3,4) in that region is

An electric field vec(E)=B x hat(i) exists in space, where B = 20 V//m^(2) . Taking the potential at (2m, 4m) to be zero, find the potential at the origin.

An electric field vec(E ) = hat(i) Cx exists in the space, where C = 10 V/ m^(2) . Taking the potential at (10 m, 20 m ) to be zero, find the potential at the origin.

Electric field strength bar(E)=E_(0)hat(i) and bar(B)=B_(0)hat(i) exists in a region. A charge is projected with a velocity bar(v)=v_(0)hat(j) at origin , then

An electric field vecE = vec I Ax exists in the space, where A= 10 V m ^(-2). Take the potential at (10m, 20m ) to be zero. Find the potential at the origin.

In figure two points A and B are located in a region of electric field . The potential difference V_(B)-V_(A) is