P (cos `theta`, - cos `theta`) , Q( sin `theta` , sin `theta`) then PQ = ......

A

`costheta`

B

`sin^2theta`

C

0

D

None

Verified by Experts

Similar Questions

Explore conceptually related problems

(3 cos theta + cos 3 theta )/( 3 sin theta - sin 3 theta ) =

If A=[(-cos theta, sin theta),(sin theta, cos theta)] then IAI=

(cos theta + sin theta )^(2) + (cos theta - sin theta )^(2) =

If cos m theta = sin n theta , then theta =

( cos 3 theta - sin 3 theta )/( cos theta+ sin theta ) =

Show that (1)/(cos theta) - cos theta = tan theta. sin theta

((cos theta - cos 3 theta ) ( sin 8 theta + sin 2 theta ))/(( sin 5 theta - sin theta )( cos 4 theta - cos 6 theta ))=

If 2-cos^(2)theta = 3 sin theta cos theta then theta =

cos theta - 4 sin theta = 1 implies sin theta + 4 cos theta =

((1+ sin theta - cos theta )/( 1+ sin theta + cos theta ))^(2)=