The relationship between speed (s), distance (d) and time (t) is given by `s=d/t` find the value of s, if d=135 meters and t= 10 seconds.

If the distance s travelled by a particle in time t is given by s=t^2-2t+5 , then its acceleration is

The distance travelled by a particle in time t is given by s=10t-7t^3 . The maximum velocity is

At time t, the distance s of a particle moving in a straight line is given by s= 4t^2+ 2t. Find the average velocity between t= 2sec and t= 8 sec.

The distance travelled by a particle in time t is given by s=(2.5)t^(2) .Find (a)the average speed of the particle during the time 0 to 5.0s, and (b)the instantanous speed at t=5.0s. Here s is in metres.

A particle is moving in a straight line with the relation between the time and the distance in such a way that s=t^3-9t^2+24t-18 . The value of its velocity when the acceleration is zero is

If the distance S travelled by a particle in time t is given by s = t^(2) - 2t + 5 then its acceleration is

A particle is moving in a straight line so that after t seconds its distance is s (in cms) from a fixed point on the line is given by s= f(t)=8t+t^3. Find the velocity at time t= 2sec (ii) the initial velocity can acceleration at t=2 sec