Home
Class 12
BIOLOGY
Select a method of breaking seed dormanc...

Select a method of breaking seed dormancy in which after ripening treatment is given at low temperature (`0-10^(@)C`) in the presence of `O_(2)`.

A

Scarification

B

Stratifiaction

C

Vernalisation

D

Photoperiodism

Text Solution

AI Generated Solution

The correct Answer is:
To break seed dormancy using a method that involves after-ripening treatment at low temperatures (0-10°C) in the presence of oxygen, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Seed Dormancy**: Seed dormancy is a survival mechanism that prevents seeds from germinating until conditions are favorable. Different methods can be used to break this dormancy. 2. **Identify the Methods**: The options provided include: - Scarification - Stratification - Vernalization - Photoperiodism 3. **Analyze Each Method**: - **Scarification**: This method involves physically breaking or weakening the seed coat to promote germination. It does not specifically involve low temperatures or oxygen. - **Stratification**: This method involves placing seeds in a moist environment at low temperatures (0-10°C) to simulate winter conditions, which helps to break dormancy. Oxygen is typically present in this process. - **Vernalization**: This process is aimed at inducing flowering in plants by exposing them to cold temperatures but does not directly relate to seed dormancy. - **Photoperiodism**: This refers to how plants respond to the length of day and night, which is not related to breaking seed dormancy. 4. **Select the Correct Method**: Based on the analysis, the method that fits the criteria of breaking seed dormancy through after-ripening treatment at low temperatures (0-10°C) in the presence of oxygen is **Stratification**. 5. **Conclusion**: Therefore, the correct answer to the question is **Stratification**.
Promotional Banner

Topper's Solved these Questions

  • PLANT GROWTH AND DEVELOPMENT

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - A)|50 Videos
  • PLANT GROWTH AND DEVELOPMENT

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION -B)|35 Videos
  • PLANT GROWTH AND DEVELOPMENT

    AAKASH INSTITUTE ENGLISH|Exercise TRY YOURSELF|52 Videos
  • PHOTOSYNTHESIS IN HIGHER PLANTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment(section D)|10 Videos
  • PLANT KINGDOM

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION -D (Assertion - Reason Type Questions)|10 Videos

Similar Questions

Explore conceptually related problems

A process of breaking seed dormancy of some plants in which seeds are treated in moist medium at low temperature (5-10^(@)C) for period of time is known as.

Haemoblobin is a Fe containing protein responsible for oxygen transport in the blood. The curves given below indicate the percentage suturation of haemoglobin by O_(2) as a funcion of partial pressure of O_(2) . Which of the following statement/s is/are correct for the given curves? I. In presence of CO_(2) , higher P_(O_(2)) is needed for a given percentage saturation. II. In presence of CO_(2) , lower P_(O_(2)) is needed for a give percentage saturation. III. The maximum percentgae saturation is not affected by the presence of CO_(2) IV. In the absence of CO_(2) , maximum saturation of haemoglobin occurs at lower p_(O_(2)) .

O_(2) and SO_(2) gases are filled in ratio of 1 : 3 by mass in a closed container of 3 L at temperature of 27^(@)C . The partial pressure of O_(2) is 0.60 atm, the concentration of SO_(2) would be

The vapour pressure of water at 80^(@)C is 355 mm of Hg. 1 L vessel contains O_(2) at 80^(@)C , which is saturated with water and the total pressure being 760 mm of Hg. The contents of the vessel were pumped into 0.3 L vessel at the same temperature. What is the partial presure of O_(2) ?

Treatment of seed at low temperature under moist conditions to break its dormancy is called

A mixture of a mol of C_(3) H_(8) and b mol of C_(2) H_(4) was kept is a container of V L exerts a pressure of 4.93 atm at temperature T . Mixture was burnt in presence of O_(2) to convert C_(3) H_(8) and C_(2) H_(4) into CO_(2) in the container at the same temperature. The pressure of gases after the reaction and attaining the thermal equilirium with atomsphere at temperature T was found to be 11.08 atm. The moles of O_(2) needed for combustion at temperature T is equal to

The co-efficient of thermal expansion of a rod is temperature dependent and is given by the formula alpha = aT , where a is a positive constant at T "in"^(@)C . if the length of the rod is l at temperature 0^(@)C , then the temperature at which the length will be 2l is

Given that C(x)=x+40 an R(x)=10x-0.2x^(2) , find the break even point.

A mixture of a mol of C_(3) H_(8) and b mol of C_(2) H_(4) was kept is a container of V L exerts a pressure of 4.93 atm at temperature T . Mixture was burnt in presence of O_(2) to convert C_(3) H_(8) and C_(2) H_(4) into CO_(2) in the container at the same temperature. The pressure of gases after the reaction and attaining the thermal equilirium with atomsphere at temperature T was found to be 11.08 atm. The mole fraction of C_(2)H_(4) in the mixture is

The sodium salt of a carboxylic acid (A) was produced by passing a gas (B) into an aqueous solution of caustic alkali at an envolved temperature and pressure (A) on heating in the presence of sodium hydroxide followed by the treatment with sulphuric acid gave a dibasic acid (C) . A sample of 0.4 gm of acid (C) on combustion gave 0.08 gm of water, .39gm of CO_2 and weighting 1.0 gm on ignition yielded 0.71 gm of silver as residue. Identify (A), (B), and (C) .