For net primary productivity energy captured is

Options

A. `1-5%` of incident radiation
B. `2-5%` of PAR
C. `0.8 -4%` of incident radiation
D. `2-10%` of PAR

Answer

To solve the question regarding net primary productivity and the percentage of energy captured, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Net Primary Productivity (NPP)**:
- NPP refers to the amount of organic matter (biomass) produced by plants through photosynthesis after accounting for the energy used in respiration. It is a measure of the energy available to the next trophic levels in an ecosystem.

2. **Identify the Types of Radiation**:
- The question mentions two types of radiation: incident radiation and photosynthetically active radiation (PAR).
- Incident radiation refers to the total solar energy that reaches the Earth's surface.
- PAR is the portion of sunlight (400 to 700 nanometers) that plants can use for photosynthesis.

3. **Determine the Percentage of Energy Captured**:
- According to the information provided in the transcript, about 50% of the total sunlight is in the PAR range.
- However, only 1-2% of PAR is actually absorbed by plants during photosynthesis.

4. **Analyze the Given Options**:
- The options provided are:
1. 1 to 5% of incident radiation
2. 2 to 5% of PAR
3. 0.4% of incident radiation
4. 2 to 10% of PAR
- Since we know that 1-2% of PAR is absorbed by plants, we can infer that the closest option that reflects this absorption rate is "2 to 5% of PAR".

5. **Conclude the Correct Answer**:
- Therefore, the correct answer to the question is **2 to 5% of PAR**.

### Summary of the Solution:
The energy captured for net primary productivity is best represented by the option **2 to 5% of PAR**, as it closely aligns with the known absorption rates of plants during photosynthesis.