In B-DNA, one full turn of the helical strand contains

Options

A. 11 base pairs
B. 8 base pairs
C. 10 base pairs
D. 9 base pairs

Answer

To solve the question about how many base pairs are contained in one full turn of the helical strand of B-DNA, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure of B-DNA**:
- B-DNA is one of the most common forms of DNA in cells. It has a right-handed helical structure.

2. **Identify the Key Measurement**:
- The question specifically asks for the number of base pairs in one full turn of the helical strand.

3. **Know the Characteristics of B-DNA**:
- In B-DNA, one full turn of the helix measures approximately 34 angstroms in length.

4. **Determine the Number of Base Pairs**:
- It is established that one full turn of B-DNA contains **10 base pairs**. This is a fundamental characteristic of B-DNA.

5. **Evaluate the Options**:
- The options provided are:
- 11 base pairs
- 8 base pairs
- 10 base pairs
- 9 base pairs
- From our understanding, the correct answer is **10 base pairs**.

6. **Conclude the Answer**:
- Therefore, the answer to the question "In B-DNA, one full turn of the helical strand contains" is **10 base pairs**.