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In a population of 1000 individuals 360 ...

In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is

A

0.4

B

0.5

C

0.6

D

0.7

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The correct Answer is:
To find the frequency of allele A in the given population, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Genotype Counts**: - Genotype AA: 360 individuals - Genotype Aa: 480 individuals - Genotype aa: 160 individuals - Total population = 1000 individuals 2. **Calculate the Frequency of Each Genotype**: - Frequency of AA (p²) = Number of AA individuals / Total population = 360 / 1000 = 0.36 - Frequency of Aa (2pq) = Number of Aa individuals / Total population = 480 / 1000 = 0.48 - Frequency of aa (q²) = Number of aa individuals / Total population = 160 / 1000 = 0.16 3. **Use the Hardy-Weinberg Principle**: - According to the Hardy-Weinberg principle, the sum of the frequencies of the genotypes must equal 1: \[ p^2 + 2pq + q^2 = 1 \] - Here, p² represents the frequency of AA, 2pq represents the frequency of Aa, and q² represents the frequency of aa. 4. **Determine the Frequency of Allele A (p)**: - We know that: \[ p^2 = 0.36 \] - To find p (the frequency of allele A), we take the square root of p²: \[ p = \sqrt{0.36} = 0.6 \] 5. **Conclusion**: - The frequency of allele A in the population is 0.6. ### Final Answer: The frequency of allele A in the population is **0.6**. ---
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