Draw the Lewis structure of `ClO_(4)` (per chlorate ion)

Explanation

To draw the Lewis structure of the per chlorate ion (ClO₄⁻), we will follow these steps:

### Step 1: Determine the total number of valence electrons
- Chlorine (Cl) has 7 valence electrons (Group 17).
- Each Oxygen (O) has 6 valence electrons, and there are 4 Oxygens: 4 × 6 = 24 valence electrons.
- The ion has a -1 charge, which means we add 1 more electron.

**Total valence electrons = 7 (from Cl) + 24 (from O) + 1 (for the charge) = 32 valence electrons.**
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