The bond between carbon atom (1) and carbon atom (2) in the compound `N -= C - CH = CH_(2)` in involves the hybridisation as :

Options

A. sp and `sp^(2)`
B. `sp^(2)` and `sp^(3)`
C. sp and `sp^(3)`
D. sp and sp

Answer

To determine the hybridization of the bond between carbon atom (1) and carbon atom (2) in the compound \( N \equiv C - CH = CH_2 \), we can follow these steps:

### Step 1: Identify the Structure
The compound can be represented as follows:
- Carbon atom 1 (C1) is part of a triple bond with nitrogen (N).
- Carbon atom 2 (C2) is connected to C1 with a single bond and is also connected to another carbon atom (C3) with a double bond.

### Step 2: Determine the Hybridization of Carbon Atoms
- **For Carbon 1 (C1)**:
- C1 is involved in a triple bond with nitrogen (N). A triple bond consists of one sigma bond and two pi bonds.
- Therefore, the hybridization of C1 is \( sp \) (since it forms two pi bonds and one sigma bond).

- **For Carbon 2 (C2)**:
- C2 is connected to C1 with a single bond and to C3 with a double bond.
- The double bond consists of one sigma bond and one pi bond, while the single bond contributes one sigma bond.
- Thus, C2 has one pi bond and two sigma bonds, leading to a hybridization of \( sp^2 \).

### Step 3: Conclusion
The bond between carbon atom (1) and carbon atom (2) involves hybridization as \( sp \) for C1 and \( sp^2 \) for C2. Therefore, the correct answer is:

**Hybridization: \( sp \) for C1 and \( sp^2 \) for C2.**

### Final Answer
The bond between carbon atom (1) and carbon atom (2) in the compound \( N \equiv C - CH = CH_2 \) involves hybridization as \( sp \) and \( sp^2 \).