Home
Class 12
CHEMISTRY
Pick out the isoelectronic structures fr...

Pick out the isoelectronic structures from the following
(i) `CH_(3)^(+)` , (ii) `H_(3)O^(+)`
(iii) `NH_(3)` , (iv) `CH_(3)^(-)`

A

Option 1. (i) and (ii)

B

Option 2. (iii) and (iv)

C

Option 3. (i) and (iii)

D

Option 4. (ii) , (iii) and (iv)

Text Solution

AI Generated Solution

The correct Answer is:
To determine the isoelectronic structures from the given options, we need to calculate the total number of electrons in each species. Isoelectronic species are those that have the same number of electrons. ### Step-by-Step Solution: 1. **Calculate the number of electrons in CH₃⁺ (Methyl cation)**: - Carbon (C) has an atomic number of 6, which means it has 6 electrons. - Each hydrogen (H) has 1 electron, and there are 3 hydrogens, contributing a total of 3 electrons. - The positive charge indicates a loss of 1 electron. - Total electrons = 6 (C) + 3 (H) - 1 (charge) = 8 electrons. 2. **Calculate the number of electrons in H₃O⁺ (Hydronium ion)**: - Oxygen (O) has an atomic number of 8, which means it has 8 electrons. - Each hydrogen contributes 1 electron, and there are 3 hydrogens, contributing a total of 3 electrons. - The positive charge indicates a loss of 1 electron. - Total electrons = 8 (O) + 3 (H) - 1 (charge) = 10 electrons. 3. **Calculate the number of electrons in NH₃ (Ammonia)**: - Nitrogen (N) has an atomic number of 7, which means it has 7 electrons. - Each hydrogen contributes 1 electron, and there are 3 hydrogens, contributing a total of 3 electrons. - Total electrons = 7 (N) + 3 (H) = 10 electrons. 4. **Calculate the number of electrons in CH₃⁻ (Methyl anion)**: - Carbon (C) has 6 electrons. - Each hydrogen contributes 1 electron, and there are 3 hydrogens, contributing a total of 3 electrons. - The negative charge indicates a gain of 1 electron. - Total electrons = 6 (C) + 3 (H) + 1 (charge) = 10 electrons. 5. **Compare the total number of electrons**: - CH₃⁺ has 8 electrons. - H₃O⁺ has 10 electrons. - NH₃ has 10 electrons. - CH₃⁻ has 10 electrons. From the calculations, we can see that H₃O⁺, NH₃, and CH₃⁻ all have 10 electrons, making them isoelectronic. Therefore, the isoelectronic structures are H₃O⁺, NH₃, and CH₃⁻. ### Conclusion: The correct answer is that the isoelectronic structures are the 2nd, 3rd, and 4th options.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - C Objective Type Questions(More than one options are correct )|13 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - D (Linked Comprehension Type Questions)|12 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section -A Objective Type Questions (One option is correct)|60 Videos
  • BIOMOLECULES

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE (ASSIGNMENT) SECTION - D Assertion - Reason Type Questions|5 Videos
  • CHEMICAL KINETICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION D : Assertion - Reason Type Questions)|15 Videos

Similar Questions

Explore conceptually related problems

Iso-structural species among the following are (l) CH_(3)^(+)(ll)H_(3)O^(+)(lll)NH_(3)(IV)CH_(3)^(-)

Identify the electrophile center in the following : (i) CH_(3)CHO" " (ii) CH_(3)CH=CH_(2)" " (iii) CH_(3)COCH_(3)

Knowledge Check

  • The order of decreasing stability of the following carbanions is (i) (CH_(3))_(3)C^(-) (ii) (CH_(3))_(2)CH^(-) (iii) CH_(3)CH_(2)^(-) (iv) C_(6)H_(5)CH_(2)^(-)

    A
    (i)gt(ii)gt(iii)gt(iv)
    B
    (iv)gt(iii)gt(ii)gt(i)
    C
    (iv)gt(i)gt(ii)gt(iii)
    D
    (iii)gt(ii)gt(i)gt(Iv)
  • Similar Questions

    Explore conceptually related problems

    Which of the following molecules are homoatomic ? (i) H_(2)O , (ii) O_(3) , (iii) NH_(3) , (iv) Cl_(2)

    Give the conjugate bases of (i) H_(2)O (ii) HNO_(3) (iii) NH_(4)^(+) (Iv) HCO_(3)^(-).

    Predict which out of the following species are planar. (i) NH_(4)^(+) (ii)CH_(3)^(+)(ii)SF_(4)(iv)OF_(2)(v)H_(2)O

    Which out of the following has the highest boiling point ? (i) C_(2)H_(5)OH " "(ii) C_(2)H_(5)Br" "(iii) CH_(3)OH (iv) C_(3)H_(6)" " (v) CH_(3)OCH_(3).

    Which structural isomerism is exhinited by the following pairs : (i) CH_(3)-(C)-OH and (C)-O-CH_(3) H- (ii) CH_(2) =CHOH and CH_(3)-overset(O)overset("||")(C)-H (iii) CH_(3)-CH_(2)-CH=CH_(2) and CH_(3)-CH=CH-CH_(3) (iv) CH_(3)-CH_(2)-CH_(2)-NH_(2) and CH_(3)-underset(NH_(2))underset("|")(CH)-CH_(3)

    Predict the products of the following reactions : (i) CH_(3)-CH_(2)-CH_(2)-O-CH_(3)+HBrrarr (ii) (iii) (iv) (CH_(3))_(3)C-OC_(2)H_(5)+HIrarr

    Arrange the following compounds in increasing order of boiling points : (i) C_(3)H_(8) (ii) C_(2)H_(5)OH (iii) CH_(3)CHO (iv) CH_(3)COOH