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In which conversion , bond length decrea...

In which conversion , bond length decreases ?

A

`N_(2) to N_(2)^(+)`

B

`N_(2) to N_(2)^(-)`

C

`CO to CO^(+)`

D

`O_(2) to O_(2)^(-)`

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The correct Answer is:
To determine in which conversion the bond length decreases, we need to analyze the hybridization changes in the given options. A decrease in bond length typically occurs when the hybridization changes from a lower s-character to a higher s-character, as higher s-character leads to stronger, shorter bonds. ### Step-by-Step Solution: 1. **Identify the Hybridization of the Atoms in Each Option**: - **Option 1: Ammonia (NH₃) and Ammonium Ion (NH₄⁺)** - For NH₃: Nitrogen has 5 valence electrons, and with 3 hydrogen atoms (1 valence electron each), the total is 8 valence electrons. This gives us 4 electron pairs (8/2 = 4), leading to sp³ hybridization. - For NH₄⁺: The calculation is similar, but we subtract 1 for the positive charge. The total remains 8 valence electrons, resulting in sp³ hybridization as well. - **Conclusion**: No change in hybridization. 2. **Option 2: Boron Trifluoride (BF₃) and Tetrafluoroborate Ion (BF₄⁻)** - For BF₃: Boron has 3 valence electrons, and with 3 fluorine atoms (7 valence electrons each), we have a total of 24 valence electrons. This gives us 3 electron pairs (24/8 = 3), leading to sp² hybridization. - For BF₄⁻: The calculation adds 1 for the negative charge, resulting in 32 valence electrons and 4 electron pairs (32/8 = 4), leading to sp³ hybridization. - **Conclusion**: Hybridization changes from sp² to sp³. 3. **Option 3: Ethyne (C₂H₂) and Ethane (C₂H₆)** - For C₂H₂: Each carbon is sp hybridized (2 electron pairs). - For C₂H₆: Each carbon is sp³ hybridized (4 electron pairs). - **Conclusion**: Hybridization changes from sp to sp³. 4. **Determine the Bond Length Changes**: - In both options 2 and 3, the hybridization changes from a lower s-character (sp² in BF₃ and sp in C₂H₂) to a higher s-character (sp³ in BF₄⁻ and C₂H₆). This indicates that the bond lengths decrease in these conversions. ### Final Answer: The bond length decreases in the conversions from BF₃ to BF₄⁻ and from C₂H₂ to C₂H₆.
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AAKASH INSTITUTE ENGLISH-CHEMICAL BONDING AND MOLECULAR STRUCTURE -Assignment Section - B Objective Type Questions(One option is correct)
  1. The ion that is isoelectronic with CO is

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  2. CO(2) is isostructural with

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  3. When NH(3) is treated with HCl, H-N-H bond angle

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  4. Among KO2 , AlO(2)^(-) BaO2 and NO2^+ unpaired electron is present in...

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  5. Correct order of bond angle for O-P-X P{:(O),(/),( "\" ),(X):} in ...

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  6. Which of the following is non-linear ?

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  7. Which of the following is electron deficient (Lewis acid ) ?

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  8. In which of the following set of compounds , bond angle remains consta...

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  9. Which of the following compounds have zero dipole moment ?

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  10. Pick out the isoelectronic structures from the following (i) CH(3)^(...

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  11. The type of hybrid orbitals used by chlorine atom in ClO(2)^(-) is :

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  12. Which of the following molecule is of T -shape ?

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  13. The molecule which has pyramidal shape is

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  14. Which of the following compounds is non-polar ?

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  15. Polarization involves the distortion of the shape of an anion by an ad...

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  16. Arrange the given species in increasing order of O-O bond length und...

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  17. In which of the following , central atom does not have one lone pairs ...

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  18. In which conversion , bond length decreases ?

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  19. Which of the following combination of orbitals will form a nonbonding ...

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  20. Correct order for N-O bond length in the given species is underset(I...

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