How many no. of `sigma`-bonds are present in `H_(2)SO_(4)` ?

Answer

To determine the number of sigma bonds in sulfuric acid (H₂SO₄), we can follow these steps:

### Step 1: Draw the Lewis Structure of H₂SO₄
- Sulfuric acid consists of one sulfur atom (S), four oxygen atoms (O), and two hydrogen atoms (H).
- The sulfur atom is the central atom, bonded to four oxygen atoms.
- Two of the oxygen atoms are connected to sulfur via double bonds, and the other two are connected via single bonds to hydrogen atoms.

### Step 2: Identify the Types of Bonds
- In the Lewis structure, we can identify the types of bonds:
- There are two S=O double bonds.
- There are two S–O single bonds (which are also connected to H atoms).

### Step 3: Count the Sigma Bonds
- Each single bond (S–O and H–O) is a sigma bond.
- Each double bond (S=O) consists of one sigma bond and one pi bond.
- Therefore:
- From the two S–O single bonds, we have 2 sigma bonds.
- From the two S=O double bonds, we have 2 sigma bonds (one from each double bond).

### Step 4: Calculate the Total Number of Sigma Bonds
- Total sigma bonds = Sigma bonds from single bonds + Sigma bonds from double bonds
- Total sigma bonds = 2 (from S–O single bonds) + 2 (from S=O double bonds) = 4 sigma bonds.

### Step 5: Add the Sigma Bonds from the H–O Bonds
- Each of the two hydrogen atoms forms a single bond with an oxygen atom (H–O), contributing 2 additional sigma bonds.

### Final Count
- Total sigma bonds = 4 (from S–O and S=O) + 2 (from H–O) = 6 sigma bonds.

Thus, the total number of sigma bonds in H₂SO₄ is **6**.

---