What will be the bond order between O - O in peroxide of sodium ?

Answer

To determine the bond order between the O-O bond in sodium peroxide (Na2O2), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Sodium Peroxide**:
Sodium peroxide has the formula Na2O2. In its structure, each sodium ion (Na⁺) is associated with a peroxide ion (O2²⁻). The peroxide ion consists of two oxygen atoms connected by a single bond.

2. **Draw the Lewis Structure**:
In the Lewis structure of the peroxide ion (O2²⁻), the two oxygen atoms are bonded together by a single bond. Each oxygen atom carries a negative charge due to the overall -2 charge of the peroxide ion.

3. **Determine the Type of Bond**:
The bond between the two oxygen atoms in the peroxide ion is a single bond. This means that there is one pair of shared electrons between the two oxygen atoms.

4. **Calculate the Bond Order**:
Bond order is defined as the number of bonding pairs of electrons divided by the number of bond connections. In this case, since there is only one bond (a single bond) between the two oxygen atoms, the bond order can be calculated as:
\[ \text{Bond Order} = \frac{\text{Number of bonding pairs}}{\text{Number of bonds}} = 1 \]

5. **Conclusion**:
Therefore, the bond order between the O-O bond in sodium peroxide is 1.

### Final Answer:
The bond order between O - O in sodium peroxide is **1**.