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Why XeF(5)^(-) is planar ?...

Why `XeF_(5)^(-)` is planar ?

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To determine why \( \text{XeF}_5^{-} \) is planar, we can follow these steps: ### Step 1: Determine the Hybridization To find the hybridization of the central atom (xenon in this case), we use the formula: \[ X = \text{(valence electrons of central atom)} + \text{(number of surrounding monovalent atoms)} - \text{(charge on cation)} + \text{(charge on anion)} \] ...
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Oxidation number of Xe in XeF_(5)^(-) is :

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The shapes of XeF_(4),XeF_(5)^(-) and SnCl_(2) are :

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Match the Xenon compounds Column-I with its structure in Column-II and assign the correct code : {:("Column-I","Column-II"),((a)XeF_(4),(i)"pyramidal"),((b)XeF_(6),(ii)" square planar"),((c)XeOF_(4),(iii)" distored octahedral"),((d) XeO_(3),(iv)" square pyramidal"):}

Assertion : The shape of XeF_(4) is square- planar. Reason : In an octahedral geometry, a single lone pair can occupy any position but a second lone pair will occupy the opposite position to the first lone pair.

Assertion : The shape of XeF_(4) is square- planar. Reason : In an octahedral geometry, a single lone pair can occupy any position but a second lone pair will occupy the opposite position to the first lone pair.

Assertion : XeF_(2) is linear Reason :Xe atom in XeF_(2) is sp hybridised