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Balance the following by ion electron me...

Balance the following by ion electron method is basic medium.
`NO_(3)^(ө)+Znrarr Zn^(2+)+NH_(4)^(oplus)`.

Text Solution

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(ii) `Zn to Zn^(2+)` ( Oxidation half reaction )
`NO_(3)^(-) to NH_(4)^(+)` (Reduction half reaction)
(iii) Balancing `e^(-)`
`Zn to Zn^(2+) + 2e^(-)`
`NO_(3)^(-) + 8e^(-) to NH_(4)^(+)`
(iv) Balancing 'O'
`Zn to Zn^(2+) + 2e^(-)`
`NO_(3)^(-)+ 8e^(-) to NH_(4)^(-) + 3H_(2)O`
(v) Balancing 'H'
`NO_(3)^(-) + 8e^(-) + 10H_(2)O to NH_(4)^(+) + 3H_(2)O + 10OH^(-)`
`Zn to Zn^(2+) + 2e^(-)`
`NO_(3)^(-) + 7H_(2)O + 8e^(-) to NH_(4)^(+) + 10OH^(-)`
Now, `[Zn to Zn^(+) + 2e^(-)]xx4`
`ul( NO_(3)^(-) + 7H_(2)O+ 8e^(-) to NH_(4)^(+) + 10OH^(-))`
(4Zn+NO_(3)^(-) + 7H_(2)O to 4Zn^(2+) + NH_(4)^(+) + 10OH^(-)`
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