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STATEMENT-1: Equivalent mass of KMnO(4) ...

STATEMENT-1: Equivalent mass of `KMnO_(4)` in different mediums are different
STATEMENT-2 `KMnO_(4)` can act as a oxidising agent .

A

Statement -1 is True, Statement -2 is True, Statement -2 is a correct explanation for Statmenet -1.

B

Statement -1 is True, Statement -2 is True, Statement-2 is NOT a correct explanation for Statement -1

C

Statement -1 is True, Statement -2 is False

D

Statement -1 is False, Statmenet -2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements regarding the equivalent mass of KMnO4 in different mediums and its role as an oxidizing agent, we can break down the solution into clear steps: ### Step 1: Understanding Equivalent Mass - **Definition**: The equivalent mass of a substance is defined as the molecular mass divided by the valency factor (n factor). - **Formula**: Equivalent mass = Molecular mass / n factor ### Step 2: Identifying the n Factor for KMnO4 - **In Acidic Medium**: - KMnO4 has Mn in the +7 oxidation state. - In acidic medium, Mn is reduced from +7 to +2. - Change in oxidation state = 7 - 2 = 5. - Therefore, n factor = 5. - **In Basic Medium**: - KMnO4 has Mn in the +7 oxidation state. - In basic medium, Mn is reduced from +7 to +6. - Change in oxidation state = 7 - 6 = 1. - Therefore, n factor = 1. - **In Neutral Medium**: - KMnO4 has Mn in the +7 oxidation state. - In neutral medium, Mn is reduced from +7 to +4. - Change in oxidation state = 7 - 4 = 3. - Therefore, n factor = 3. ### Step 3: Calculating Equivalent Mass in Different Mediums - **Acidic Medium**: - Equivalent mass = Molecular mass / 5 - **Basic Medium**: - Equivalent mass = Molecular mass / 1 - **Neutral Medium**: - Equivalent mass = Molecular mass / 3 ### Step 4: Conclusion on Statement 1 - **Statement 1**: "Equivalent mass of KMnO4 in different mediums are different." - This statement is **true** because the n factor varies in different mediums, leading to different equivalent masses. ### Step 5: Analyzing Statement 2 - **Statement 2**: "KMnO4 can act as an oxidizing agent." - KMnO4 is indeed an oxidizing agent as it can oxidize other substances while being reduced itself. - This statement is also **true**. ### Step 6: Relationship Between the Statements - While both statements are true, Statement 2 does not explain Statement 1. The difference in equivalent mass arises from the different n factors in various mediums, not directly from the oxidizing property of KMnO4. ### Final Answer - Both statements are true, but Statement 2 does not correctly explain Statement 1. Therefore, the answer is: **Both statements are true, but Statement 2 is not the correct explanation for Statement 1.** ---
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n-Factor of KMnO_(4) in neutral medium is

Equivalent mass of KMnO_(4) in acidic basic and netural are in the ratio, of:

STATEMENT-1: The equivalent mass of of KMnO_(4) in acidic medium is (M)/(5) where M=molecular mass of KMnO_(4) STATEMENT-2: Equivalent mass is equal to product of molecular mass and change in oxidation number.

STATEMENT-1 KMnO_(4) acts as powerful oxidising agent in acids, alkaline and neutral medium. STATEMENT-2: Equivalent weight of KMnO_(4) in acidic medium in M/5 and in strongly alkaline medium in M/3. STATEMENT-3 : KMnO_(4) solution is used as a primary standard and acts as self indicator during its titration more Mohr salt.

For KMnO_(4) in neutral medium correct combination is -

0.1 M solution of KMnO_(4) (in acidic medium) may oxidies

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): Equivalent mass of KMnO_(4) is equal to one-fifth of its molecular mass when it acts as oxidising agent in mild basic medium. Reason (R): Oxidation number of Mn in KMnO_(4) is +7 .

STATEMENT-1: KMnO_(4) , is purple in colour due to charge transfer. and STATEMENT-2: In MnO_(4)^- , there is no electron present in d-orbitals of manganese.

STATEMENT-1 : MnO_(4)^(-) is tetrahedral in shape . and STATEMENT-2: KMnO_(4) is purple in colour .

A : Equivalent weight of KMnO_(4) in acidic medium is M/5 . R : In acidic medium 1 mol of MnO_(4)""^(-) gains 5 electron.