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STATEMENT-1: The equivalent mass of of K...

STATEMENT-1: The equivalent mass of of `KMnO_(4)` in acidic medium is `(M)/(5)` where M=molecular mass of `KMnO_(4)`
STATEMENT-2: Equivalent mass is equal to product of molecular mass and change in oxidation number.

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STATEMENT-1 KMnO_(4) overset("acidic medium")to Mn^(2+) , n factor of KMnO_(4) is 5 and STATEMENT-2 Equivalent mass of KMnO_(4) in acidic medium is (M)/(5) (M=molecular mass of KMnO_(4) )

A : Equivalent weight of KMnO_(4) in acidic medium is M/5 . R : In acidic medium 1 mol of MnO_(4)""^(-) gains 5 electron.