KF and NaCl struture. If the distance between ` K ^(+) and F^(-)` is 269 pm, find the denisty of KF ( ` N_(A) = 6.02 xx 10^(23) "mol"^(-1)` a atomic mass of copper = 63.5

Explanation

To find the density of KF given the distance between \( K^+ \) and \( F^- \) is 269 pm, we can follow these steps:

### Step 1: Convert the distance to appropriate units
The distance between \( K^+ \) and \( F^- \) is given as 269 pm (picometers). We need to convert this to centimeters for our calculations.

\[ \text{Distance (R)} = 269 \text{ pm} = 269 \times 10^{-12} \text{ m} = 269 \times 10^{-10} \text{ cm} \]
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