A compound AB crystallises in bcc lattice with the unit cell edge length of 380 pm . Calculate (i) The distance between oppositely charged Ions in the lattic.
(ii)Radius of `B^(−)` if the radius of `A^(+)` is 190 pm.

Explanation

To solve the problem step by step, we will address both parts of the question systematically.

### Given:
- Compound AB crystallizes in a Body-Centered Cubic (BCC) lattice.
- Unit cell edge length (a) = 380 pm
- Radius of A⁺ (r₁) = 190 pm

### (i) Calculate the distance between oppositely charged ions in the lattice.
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