Home
Class 12
CHEMISTRY
All spinel structures do not have...

All spinel structures do not have

A

CCP array of anions

B

Simple cubic structure

C

BCC array of anions

D

HCP array of anions

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question "All spinel structures do not have:", we need to analyze the characteristics of spinel structures and the types of arrangements of anions mentioned in the options. ### Step-by-step Solution: 1. **Understanding Spinel Structures**: - Spinel structures are a type of crystal structure that typically consist of cations and anions. The most common formula for spinel is AB₂O₄, where 'A' and 'B' are cations, and 'O' represents oxide anions. - In a spinel structure, the anions (O²⁻) occupy the face-centered cubic (FCC) lattice points. **Hint**: Recall the general formula and arrangement of spinel structures. 2. **Identifying the Anion Arrangement**: - The anions in spinel structures occupy the FCC lattice, which is also referred to as cubic close packing (CCP). This means that the anions are arranged in a specific three-dimensional pattern that maximizes space efficiency. **Hint**: Remember that FCC and CCP refer to the same arrangement of anions. 3. **Analyzing the Options**: - **Option A: CCP array of anions**: This is present in spinel structures since the anions occupy the FCC lattice. - **Option B: Simple cubic structure**: This arrangement is not typical for spinel structures. Spinel does not have a simple cubic arrangement of anions. - **Option C: BCC array of anions**: Spinel structures do not have a body-centered cubic arrangement for anions. - **Option D: HCP array of anions**: Spinel structures do not have a hexagonal close-packed arrangement. **Hint**: Compare each option with the known structure of spinels. 4. **Conclusion**: - Since spinel structures do not have simple cubic, BCC, or HCP arrangements of anions, the correct answer to the question is that all spinel structures do not have: - **B: Simple cubic structure** - **C: BCC array of anions** - **D: HCP array of anions** ### Final Answer: All spinel structures do not have: - **B: Simple cubic structure** - **C: BCC array of anions** - **D: HCP array of anions**
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-D (LINKED COMPREHENSION)|9 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-E (ASSERTION-REASON)|10 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-B (OBJECTIVE)|27 Videos
  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-J)|10 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (Section -D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

What kind of cell structure do protists have, prokaryotic or eukaryotic ?

MgFe_2 O_4 has spinel structure , then the percentge of tetrahedral voids and the octahedral voids occupied are respectively

In the spinel structur, oxides ions are cubical-closet packed whereas 1/8th of tetrahedral voids are occupied by A^(2+) cation and 1/2 of octahedral voids are occupied by B^(+) cations. The general formula of the compound having spinel structure is:

In normal spinel structure there is a closed packed array of O^(2-) ions. The trivalent cations are present in

Fe_3O_4 has inverse spinel structure. What is not true about this solid ?

In a normal spinel types structure, the oxide ions are arranged in ccp whereas 1/8 tetrahedral holes are occupied by Zn^(2+) ions and 50% of octahedral holes are occupied by Fe^(3+) ions. The formula of the compound is -

Which of the following pairs of structures do not represent isomers?

Cryptogams do not have

The spinel structure consists of an array of O^(2-) ions in fcc arrangement. Gereral formula of spinel is AB_(2)O_(4) . Cations of A occupy 1/8th the tetrahedral voids and cations of B ions occupy half of the octahedral voids. If oxide ions are replaced by X^(-8//3) ions then number of an ionic vacancy per unit cell will be