Home
Class 12
CHEMISTRY
Magnesium and Titanium form a crystallin...

Magnesium and Titanium form a crystalline oxide in which Mg appears at the eight corners , oxygen appears at face centres and titanium appears at the centre of cube. The atomic mass of magnesium , titanium and oxygen is 24, 45.9 and 16 amu respectively. A similar compound is formed by calcium with titanium and oxygen .
What would be the number of nearest neighbours for Ti ?

A

8

B

6

C

12

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of nearest neighbors for titanium (Ti) in the given crystalline structure, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Structure**: - The unit cell is a cube. - Magnesium (Mg) occupies the eight corners of the cube. - Oxygen (O) occupies the face centers of the cube. - Titanium (Ti) occupies the center of the cube. 2. **Visualizing the Unit Cell**: - Draw a cube to represent the unit cell. - Mark the corners where Mg is located. - Mark the centers of the six faces where O is located. - Mark the center of the cube where Ti is located. 3. **Identifying Nearest Neighbors**: - Titanium is located at the body center of the cube. - The nearest neighbors to Ti will be those atoms that are closest to it in the structure. 4. **Counting the Nearest Neighbors**: - The nearest neighbors for Ti will be the atoms located at the face centers of the cube. - Since there are six faces in a cube, and each face center atom is a nearest neighbor to the Ti atom at the center, Ti will have one nearest neighbor from each of the six faces. 5. **Conclusion**: - Therefore, the number of nearest neighbors for titanium (Ti) in this crystalline oxide structure is **6**. ### Final Answer: The number of nearest neighbors for Ti is **6**. ---
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-E (ASSERTION-REASON)|10 Videos

  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-F (MATRIX MATCH)|2 Videos

  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-C (OBJECTIVE)|17 Videos

  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-J)|10 Videos

  • THERMODYNAMICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (Section -D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

Magnesium and Titanium form a crystalline oxide in which Mg appears at the eight corners , oxygen appears at face centres and titanium appears at the centre of cube. The atomic mass of magnesium , titanium and oxygen is 24, 45.9 and 16 amu respectively. A similar compound is formed by calcium with titanium and oxygen . What would be the formula of substance (oxide) ?

Magnesium and Titanium form a crystalline oxide in which Mg appears at the eight corners , oxygen appears at face centres and titanium appears at the centre of cube. The atomic mass of magnesium , titanium and oxygen is 24, 45.9 and 16 amu respectively. A similar compound is formed by calcium with titanium and oxygen . What would be the molar mass of unit cell of MgTiO_3 ?

Magnesium and Titanium form a crystalline oxide in which Mg appears at the eight corners , oxygen appears at face centres and titanium appears at the centre of cube. The atomic mass of magnesium , titanium and oxygen is 24, 45.9 and 16 amu respectively. A similar compound is formed by calcium with titanium and oxygen . What type of crystalline structure does MgTiO_3 have ?

Perovskite is a mineral composed of Ca, Ti and oxygen, cations of titanium lie at the centre, oxides ions at the face centres and calcium ions lie at corners. In this compound the oxidation number of Titanium is +x . Find the value of x?

A mineral is made of calcium ,titanium and oxygen Ca^(2+) ions located at corners , Ti^(4+) ions at the body -centre and O^(2-) ions face -centred of the unit cell. The molecular formula of the mineral is :

When an atom or an ion is missing from its normal lattice site, a lattice vacancy (Schottky detect) is created In stoichiometric ionic crystals, a vacancy of one ion has to be accompanied by the vacancy of the oppositely charged ion in order to maintain electrical neutrality. In a Frenkel defect an ion leaves its position in the lattice and occupies an interstitial void.This is the Frenkel defect commonly found along with the Schottky defects and interstitials.In pure alkali halides, Frendel defect are not found since the ions cannot get into the intenstitial sites.Frenkel defects are found in silver halides because of the small size of the Ag^+ ion.Unlike Schottky defects. Frenkel defects do not change the density of the solids.In certain ionic solids (e.g. AgBr) both Schottky and Frenkel defects occur. The defects discussed above do not disturb the stoichiometry of the crystalline meterial.There is large Such solids showing deviations from the ideal stoichiometric composition form an important group of solids For example in the vanadium oxide, VO_x , x can be anywhere between 0.6 and 1.3.There are solids which are difficult to prepare in the stoichiometric composition.Thus, the ideal composition in compounds such as FeO is difficult to obtain (normally we get a composition of Fe_(0.85) O but it may range from Fe_(0.93) O to Fe_(0.96)O ).Non-stoichiometric behaviour is most commonly found for transition metal compounds through is also known for some lanthanoids and actinodes. Zinc oxide loses oxygen reversibly at high temperature and turns yellow in colour.The excess metal is accomdated interstitially, giving rise to electrons trapped in the neighbourhood.the enhanced electrical conductivity of the non-stoichiometric ZnO arises from these electrons . Anion vacancies in alkali halides are produced by heating the alkali halide crystals in an atmosphere of the alkali metal vapour.When the metal atoms deposite on the surface they diffuse into the crystal and after ionisation the alkali metal ion occupies cationic vacancy whereas electron occupies anionic vacancy.Electrons trapped in anion vacancies are referred to as F-centres (from Farbe the German word for colour) that gives rise to interesting colour in alkali halides.Thus, the excess of potassium in KCl makes the crystal appear violet and the excess of lithium in LiCl makes it pink. In the crystal of Fe_(0.93)O , the percentage of Fe (II) will be

Objective question . i. A certains compound has the molecular formula X_(4) O_(6) . If 10 g of X_(4) O_(6) has 5.72 g X , then atomic mass of X is: a. 32 amu b. 42 amu c. 98 amu d. 37 amu ii. For 109% labelled oleum, if the number of moles of H_(2)SO_(4) and free SO_(3) be p and q , respectively, then what will be the value of (p - q)/(p + q) a. 1//9 b. 9 c. 18 d. 1//3 iii. Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation, 2H_(2) O_(2) (aq) rarr 2 H_(2) O (l) + O_(2) (g) Under conditions where 1 mol gas occupies 24 dm^(3), 100 cm^(3) of X M solution of H_(2) O_(2) produces 3 dm^(3) of O_(2) . Thus, X is a. 2.5 b. 0.5 c. 0.25 d. 1 iv. 4 g of sulphur is burnt to form SO_(2) which is oxidised by Cl_(2) water. The solution is then treated with BaCl_(2) solution. The amount of BaSO_(4) precipitated is: a. 0.24 mol b. 0.5 mol c. 1 mol d. 0.125 mol v. A reaction occurs between 3 moles of H_(2) and 1.5 moles of O_(2) to give some amount of H_(2) O . The limiting reagent in this reaction is a. H_(2) and O_(2) both b. O_(2) c. H_(2) d. Neither of them vi. 4 I^(ɵ) + Hg^(2+) rarr HgO_(4)^(-) , 1 mole each of Hg^(2+) and I^(ɵ) will form: a. 1 mol of HgI_(4)^(2-) b. 0.5 mol of HgI_(4)^(-2) 0.25 mol of HgI_(4)^(2-) 2 mol of HgI_(4)^(-2)