Home
Class 12
CHEMISTRY
Calculate the closest distance between t...

Calculate the closest distance between two gold atoms (edge length =1.414 Å) in a face-centered cubic lattice of gold

Text Solution

AI Generated Solution

To calculate the closest distance between two gold atoms in a face-centered cubic (FCC) lattice, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the FCC Structure**: In a face-centered cubic lattice, atoms are located at each corner of the cube and at the center of each face of the cube. 2. **Identify the Edge Length**: The edge length (A) of the FCC lattice is given as 1.414 Å. ...
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-J (AAKASH CHALLENGERS )|10 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|30 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-H (MULTIPLE TRUE-FALSE)|3 Videos
  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-J)|10 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (Section -D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

In face -centered cubic unit cell, edge length is

In face -centered cubic unit cell, edge length is

A : In NaCl structure, the interionic distance is a/2 (a = Unit cell edge length). R : NaCl forms face centered cubic unit cell.

Metallic gold crystallizes in the fcc lattice. The length of the cubic unit cell is a = 4.242 A . a. What is the closest distance between gold atoms? b. How many "nearest neighbours" does each gold atom have at the distance calculated in (a) ? (c) What is the density of gold? (Aw of Au = 197.0 g mol^(-1) ) d. Prove that the packing factor for gold is 0.74 .

Calculate the density of diamond from the fact that it has a face-centered cubic structure with two atoms per lattice point and unit cell edge length of 3.569× 10 ^(−8) cm.

Calculate the approximate number of unit cells present in 1 g of gold. Given that gold cyrstallises in a face centred cubic lathce (Given atomic mass of gold = 197 u).

Calculate the approximate number of unit cells present in 1 g of gold. Given that gold cyrstallises in a face centred cubic lathce (Given atomic mass of gold = 197 u).

Potassium chloride crystallize with a body-centred cubic lattice. Calculate the distance between the 200, 110, and 222 Planes. The length of the side of the unit cell is 5.34 Å .

Platinum (atomic radius = 1.38 Å ) crystallises in a cubic closed packed structure. Calculate the edge length of the face-centred cubic unit cell and the density of the platinum (Pt = 195)

The magnetic moment of a gadolinium atom is 7.95 muB (Ho is the Bohr magneton). Gadolinium crystallizes in a face-centered cubic lattice with lattice constant of 3.2 Å. Find the saturation magnetization. Take into account that an elementary cell of a face-centered lattice contains four atoms.