Home
Class 12
CHEMISTRY
The pair of compound which cannot exist ...

The pair of compound which cannot exist in solution is:

A

`NaHCO_(3) and NaOH`

B

`Na_(2)SO_(3) and NaHCO_(3)`

C

` Na_(2)CO_(3) and NaOH`

D

`NaHCO_(3) and NaCl`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question about which pair of compounds cannot exist in solution, we need to analyze the given options based on their chemical properties and potential reactions. ### Step-by-Step Solution 1. **Understanding the Compounds**: - We have four pairs of compounds to analyze: - (A) Sodium bicarbonate (NaHCO3) and Sodium hydroxide (NaOH) - (B) Sodium sulphite (Na2SO3) and Sodium carbonate (Na2CO3) - (C) Sodium carbonate (Na2CO3) and Sodium hydroxide (NaOH) - (D) Sodium carbonate (Na2CO3) and Sodium chloride (NaCl) 2. **Analyzing Option A (NaHCO3 and NaOH)**: - Sodium bicarbonate (NaHCO3) is a salt of a weak acid (carbonic acid, H2CO3) and a strong base (NaOH). - When mixed, NaHCO3 can act as an acid and react with NaOH to form sodium carbonate (Na2CO3) and water (H2O). - Therefore, these two compounds will react and cannot coexist in solution. 3. **Analyzing Option B (Na2SO3 and Na2CO3)**: - Sodium sulphite (Na2SO3) and sodium carbonate (Na2CO3) are both salts and do not have any strong acid-base reaction between them. - They can exist together in solution without reacting. 4. **Analyzing Option C (Na2CO3 and NaOH)**: - Sodium carbonate (Na2CO3) is a salt of a weak acid (carbonic acid) and a strong base. - Sodium hydroxide (NaOH) is also a strong base. - There is no significant reaction between Na2CO3 and NaOH, so they can coexist in solution. 5. **Analyzing Option D (Na2CO3 and NaCl)**: - Sodium carbonate (Na2CO3) and sodium chloride (NaCl) are both salts and do not react with each other. - They can exist together in solution without any reaction. 6. **Conclusion**: - The only pair of compounds that cannot exist in solution because they react with each other is **Option A: Sodium bicarbonate (NaHCO3) and Sodium hydroxide (NaOH)**. ### Final Answer: The pair of compounds that cannot exist in solution is **Option A: Sodium bicarbonate (NaHCO3) and Sodium hydroxide (NaOH)**.
Promotional Banner

Topper's Solved these Questions

  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-D)|9 Videos
  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-E)|7 Videos
  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-B)|13 Videos
  • THE P-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section-J)|16 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - D) (ASSERTION-REASON TYPE QUESTION)|20 Videos

Similar Questions

Explore conceptually related problems

The pairs of compounds which cannot exist together in aqueous solution are

The pair of compounds which cannot exist together in aqueous solution is: (I) NaH_(2)PO_(4) and NaHCO_(3)" "(II) Na_(2)CO_(3) and NaHCO_(3) (III) NaOH and NaH_(2)PO_(2)" "(IV) NaHCO_(3) and NaOH

The pairs of compounds which cannot exist together in aquous solution are: (I) NaH_(2)PO_(4) and Na_(2)HCO_(3) (II) Na_(2)CO_(3) and NaOH (III) NaOH and NaH_(2)PO_(4) (IV) NaHCO_(3) and NaOH

The pair of compounds which can exist together in aqueous solution is

The pair of compounds that can exist together is:

The following pair that cannot exist in solution is

Which of the following pair can't exist in solution

Compound which cannot act as a reducing agent is

The compounds which cannot react with NaOH is/are

Give a chemical test to distinguish between the pairs of compounds : Sodium chloride solution and sodium carbonate solution