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Statement-1: Pure NaCl is a diliquescent...

Statement-1: Pure NaCl is a diliquescent crystalline solid.
Statement-2: `Na_(2)CO_(3)` is known as pearl ash.
Statement-3: Sulphur disproportionates in NaOH.

A

FFT

B

TTF

C

TFT

D

FFF

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement one by one and determine whether they are true or false. ### Step 1: Evaluate Statement 1 **Statement 1:** Pure NaCl is a deliquescent crystalline solid. - **Definition of Deliquescent:** A substance is considered deliquescent if it can absorb moisture from the air and dissolve in it, forming a solution. - **Analysis of NaCl:** Pure NaCl (sodium chloride) is commonly known as table salt. While it can absorb moisture under certain conditions (high humidity), it is not classified as a deliquescent substance in its pure form. Deliquescent substances typically are those that readily absorb water and dissolve, such as calcium chloride or magnesium chloride. - **Conclusion:** Therefore, **Statement 1 is false.** ### Step 2: Evaluate Statement 2 **Statement 2:** Na₂CO₃ is known as pearl ash. - **Correct Identification:** Na₂CO₃ is sodium carbonate, while K₂CO₃ is potassium carbonate, which is known as pearl ash. Pearl ash is derived from the ashes of burnt plants that contain potassium carbonate. - **Conclusion:** Thus, **Statement 2 is false.** ### Step 3: Evaluate Statement 3 **Statement 3:** Sulphur disproportionates in NaOH. - **Disproportionation Reaction:** A disproportionation reaction is a type of redox reaction where a single substance is both oxidized and reduced. - **Reaction Analysis:** The reaction can be represented as: \[ S + 2NaOH \rightarrow Na₂S + Na₂SO₃ + S \] In this reaction, the oxidation states of sulphur change: - In elemental sulphur (S), the oxidation state is 0. - In sodium sulfide (Na₂S), the oxidation state of sulphur is -2. - In sodium sulfite (Na₂SO₃), the oxidation state of sulphur is +4. - **Conclusion:** Since sulphur goes from an oxidation state of 0 to -2 (reduction) and +4 (oxidation), it indicates that sulphur is undergoing disproportionation. Therefore, **Statement 3 is true.** ### Final Summary of Statements - **Statement 1:** False - **Statement 2:** False - **Statement 3:** True Thus, the overall evaluation of the statements is: **False, False, True (FFT)**.
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