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A compound of Xe and F is found to have ...

A compound of Xe and F is found to have 53.3% Xe (At. mass =133). Oxidation number of Xe in this compound is

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To find the oxidation number of xenon (Xe) in the compound with fluorine (F), we can follow these steps: ### Step 1: Set Up the Problem We know that the compound consists of xenon and fluorine, and we can denote it as \( \text{XeF}_n \), where \( n \) is the number of fluorine atoms. We are given that the compound has 53.3% xenon by mass and the atomic mass of xenon is 133 g/mol. ### Step 2: Use the Percentage to Set Up an Equation The percentage by mass of xenon in the compound can be expressed as: \[ ...
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Oxidation number is the charge which an atom of an element has in its ion or appears to have when present in the combined state. It is also called oxidation state. Oxidation number of any atom in the elementary state is zero. Oxidation number of a monoatomic ion is equal to the charge on it. In compounds of metals with non metals, metals have positive oxidation number while non metals have negative oxidation numbers. In compounds of two difference elements, the more electronegative element has negative oxidation number whereas the other has positive oxidation number. In complex ions, the sum of the oxidation number of all the atoms is equal to the charge on the ion. If a compound contains two or more atoms of the same element, they may have same or different oxidation states according as their chemical bonding is same or different. A compound of Xe and F is found to have 53.3% Xe (atomic weight =133). Oxidation number of Xe in this compound is

A compound of Xe and F is found to have 53.3% Xe (atomic weight = 133) Oxidation number of Xe in this compound is

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