It requires 40.05 ml of 1M`Ce^(4+)` to titrate 20ml of 1 M `Sn ^(2+)` to `Sn ^(4+)` . What is the oxidation state of the cerium in the product

Explanation

To determine the oxidation state of cerium in the product after the titration of Sn²⁺ to Sn⁴⁺ using Ce⁴⁺, we can follow these steps:

### Step 1: Understand the Reaction
In this reaction, Sn²⁺ is oxidized to Sn⁴⁺, and Ce⁴⁺ is reduced. The balanced half-reactions can be written as:
- Oxidation: Sn²⁺ → Sn⁴⁺ + 2e⁻
- Reduction: Ce⁴⁺ + e⁻ → Ce³⁺

### Step 2: Calculate the Moles of Sn²⁺
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