Statement-1: `BCl_(3)` and `C Cl_(4)` do not undergo hydrolysis.
Statement-2: Both B and carbon do not have empty d-orbitals.

Options

A. Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1
B. Statement-1 is true, statement-2 is true, statement-2 is not correct explanation for statement-1
C. Statement-1 is true, statement-2 is false
D. Statement-1 is false, statement-2 is true

Answer

To solve the question, we need to analyze the two statements provided:

**Statement 1**: BCl₃ and CCl₄ do not undergo hydrolysis.
**Statement 2**: Both B and carbon do not have empty d-orbitals.

### Step 1: Analyze Statement 1
- **BCl₃**: Boron has the electronic configuration of 1s² 2s² 2p¹. In bonding, one of the 2s electrons is promoted to a 2p orbital, allowing boron to form three sp² hybrid orbitals. This results in one empty p orbital. Because of this empty orbital, BCl₃ can accept a lone pair from water (H₂O), allowing it to undergo hydrolysis to form H₃BO₃ and HCl.

- **CCl₄**: Carbon has the electronic configuration of 1s² 2s² 2p². When forming bonds, the 2s electron is promoted to a 2p orbital, resulting in four sp³ hybrid orbitals. Carbon does not have any empty orbitals available to accept a lone pair from water. Therefore, CCl₄ does not undergo hydrolysis.

**Conclusion for Statement 1**: BCl₃ can undergo hydrolysis, while CCl₄ cannot. Thus, Statement 1 is **false**.

### Step 2: Analyze Statement 2
- Both boron and carbon have their outermost electrons in the second shell (n=2), which contains only s and p orbitals. There are no d-orbitals in the second shell. Therefore, it is accurate to say that both boron and carbon do not have empty d-orbitals.

**Conclusion for Statement 2**: This statement is **true**.

### Final Conclusion
- Statement 1 is false because BCl₃ can undergo hydrolysis while CCl₄ cannot.
- Statement 2 is true because both boron and carbon do not have empty d-orbitals.

Thus, the correct answer is that Statement 1 is false and Statement 2 is true.

### Summary of the Solution
- **Statement 1**: False (BCl₃ can undergo hydrolysis; CCl₄ cannot)
- **Statement 2**: True (Both boron and carbon do not have empty d-orbitals)