Statement-1: `IC l_(2)^(Theta)` is a linear compound.
Statement-2: In `IC l_(2)^(Theta)`, I is sp hybridised.

Options

A. Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1
B. Statement-1 is true, statement-2 is true, statement-2 is not correct explanation for statement-1
C. Statement-1 is true, statement-2 is false
D. Statement-1 is false, statement-2 is true

Answer

To analyze the statements given in the question regarding ICl2⁻, we will go through the following steps:

### Step 1: Determine the Hybridization of Iodine in ICl2⁻
1. Identify the central atom: In ICl2⁻, the central atom is iodine (I).
2. Calculate the steric number using the formula:
\[ \text{Steric Number} = \frac{1}{2} \left( \text{Number of Valence Electrons of Central Atom} + \text{Number of Monovalent Atoms Attached} - \text{Charge of Cation} + \text{Charge of Anion} \right) \]
- Valence electrons of iodine (I) = 7
- Number of monovalent atoms (Cl) attached = 2
- Charge of cation = 0 (since there is no cation)
- Charge of anion = -1 (since it is ICl2⁻)

Plugging in the values:
\[ \text{Steric Number} = \frac{1}{2} \left( 7 + 2 - 0 + 1 \right) = \frac{1}{2} \times 10 = 5 \]

### Step 2: Determine the Hybridization Type
3. Based on the steric number:
- A steric number of 5 corresponds to sp³d hybridization.

### Step 3: Determine the Molecular Geometry
4. For sp³d hybridization, the geometry is trigonal bipyramidal. However, since there are three lone pairs on iodine, they will occupy the equatorial positions to minimize lone pair-lone pair repulsion.
5. The two chlorine atoms will occupy the axial positions, leading to a linear shape for the molecule.

### Step 4: Evaluate the Statements
6. Statement-1: "ICl2⁻ is a linear compound." - This statement is **True**.
7. Statement-2: "In ICl2⁻, I is sp hybridized." - This statement is **False** because I is actually sp³d hybridized.

### Conclusion
- Statement 1 is true, and Statement 2 is false. Therefore, the correct conclusion is that the first statement is correct, while the second statement is incorrect.

### Final Answer
The correct option is that Statement 1 is true and Statement 2 is false.

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