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(a) On bolining a mineral (A) with Na2CO...

(a) On bolining a mineral `(A)` with `Na_2CO_(3)` solution, a white precipirtate `(B)` is formed.
(b) The precipitate is fitered and the filtrate contains two conpounds `( C)` and `(D)`. The componds `( C)` is removed by crystallisation and when `CO_(2)` is passed through the mother liquor left, `(D)` changes to `( C)`.
( c) On strongly heating `( C)`, two compounds `(D)` and `( E)` are formed.
(d) `(E)` on heating with cobalt oxide provides blue-coloured substance `(F)`.
Identify `(A)` to `(F)` and give chemical reaction for `(a)` to `(d)`.

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AI Generated Solution

To solve the problem step by step, we need to identify the compounds A to F and provide the corresponding chemical reactions for each part of the question. ### Step 1: Identify Compound A and Reaction (a) **Compound A:** The mineral being boiled with Na2CO3 is **Colemanite**, which has the formula **Ca2B6O11·5H2O**. **Reaction (a):** When Colemanite is boiled with sodium carbonate (Na2CO3), it forms calcium carbonate (CaCO3) as a white precipitate (Compound B) and sodium borate compounds in the solution. ...
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