Home
Class 12
CHEMISTRY
For the first row transition metals the ...

For the first row transition metals the `E^(ɵ) (M^(+2)//M))` value are:
`{:(underset(-1.18)(V),,underset(-0.91)(Cr),,underset(-1.18)(Mn),,underset(-0.44)(Fe),,underset(-0.28)(Co),,underset(-0.25)(Ni),underset(+0.34)(Cu)):}`
Explain the irregularity in the above values.

Text Solution

Verified by Experts

The `E^(Ɵ)(M^(2+)//M)` values are not regular which can be explained from the irregular variation of ionisation enthalpies `(Delta_(i)H_(1)+Delta_(i)H_(2))` and also the sublimation enthalpies which are relatively much less for manganese and vanadium.
Promotional Banner

Topper's Solved these Questions

  • THE D AND F-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|15 Videos

  • THE D AND F-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assingnment(Section -A ( Objective Type Questions)(One option is correct))|50 Videos

  • Test-12

    AAKASH INSTITUTE ENGLISH|Exercise Exercise|58 Videos

  • THE P-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section-J)|16 Videos

Similar Questions

Explore conceptually related problems

For the first row transition metals the E^(ɵ) value are: {:(underset(-1.18)(V),,underset(-0.91)(Cr),,underset(-1.18)(Mn),,underset(-0.44)(Fe),,underset(-0.28)(Co),,underset(-0.25)(Ni),underset(+0.34)(Cu)):} Explain the irregularity in the above values.

(A) overset(NaNO_(2)//HCl)underset((ii)H_(2)//Ni)underset(0-5^(@))(rarr)(B) , is:

Evaluate: underset(0)overset(pi//4)intsinxdx

The value of cot (underset(n=1)overset(23)sum cot^(-1) (1 + underset(k=1)overset(n)sum 2k)) is

If overset(4)underset(-1)int f(x)=4 and overset(4)underset(2)int (3-f(x))dx=7 , then the value of overset(-1)underset(2)int f(x)dx , is

Let overset(a)underset(0)int f(x)dx=lambda and overset(a)underset(0)int f(2a-x)dx=mu . Then, overset(2a)underset(0)int f(x) dx equal to

Evaluate: underset(xrarr0)lim((1-x)^n-1)/(x)

If I=overset(1)underset(0)int (1)/(1+x^(pi//2))dx then

Student I ,II , and III perform an experiment for measuring the acceleration due to gravity (g) usinf a simple pendulum. They use lengths of the pendulum and // or record time for different number of oscillations . The observations are shown in the following table . Least count for length = 0.1 cm {:(underset(III)underset(II)underset(I)underset()underset()("Student"),underset(20.0)underset(64.0)underset(64.0)underset((cm))underset("Pendulam")("Length of "),underset(4)underset(4)underset(8)underset((n))underset("n Oscillation")("Number of"),underset(9.0)underset(16.0)underset(16.0)underset((s))underset("Period")("Time")):} Least count for time = 0.1 s . If E_(I), E_(II) , and E_(III) are the percentage errors in g , i.,e., ((Delta g)/( g) xx 100) for students I,II , and III, respectively , then

The value of overset(16pi//3)underset(0)int |sinx|dx is