Home
Class 12
CHEMISTRY
Choose the pair in which IE(1) of first ...

Choose the pair in which `IE_(1)` of first element is greater than `IE_(1)` of second element but in case of `IE_(2)` order is/are reversed

A

`Mn gt Cr `

B

`Mn gt Fe `

C

`Zn gt Cu `

D

All of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the ionization enthalpies (IE) of the given pairs of elements. We are looking for a pair where the first ionization energy (IE1) of the first element is greater than that of the second element, but the second ionization energy (IE2) of the second element is greater than that of the first element. ### Step-by-Step Solution: 1. **Identify the Elements and Their Configurations**: - We need to look at the electronic configurations of the elements in each pair to understand their ionization energies. - For example, consider the pair Manganese (Mn) and Chromium (Cr): - Mn: Atomic number 25, Configuration: [Ar] 3d5 4s2 - Cr: Atomic number 24, Configuration: [Ar] 3d5 4s1 2. **Analyze the First Ionization Energy (IE1)**: - The first ionization energy is the energy required to remove the outermost electron. - For Mn, removing an electron from 4s2 results in a configuration of 3d5 4s1. - For Cr, removing an electron from 4s1 results in a configuration of 3d5 4s0. - Since Cr has a half-filled 3d subshell, it is more stable, making it easier to remove an electron from Mn than from Cr. - Therefore, **IE1(Mn) > IE1(Cr)**. 3. **Analyze the Second Ionization Energy (IE2)**: - The second ionization energy is the energy required to remove a second electron after the first has been removed. - After the first ionization: - Mn becomes 3d5 4s1. - Cr becomes 3d5. - Removing an electron from Mn (3d5 4s1) results in a half-filled d subshell (3d5), which is relatively stable. - Removing an electron from Cr (3d5) results in a configuration of 3d4, which is less stable. - Thus, **IE2(Cr) > IE2(Mn)**. 4. **Conclusion**: - We find that for the pair (Mn, Cr): - **IE1(Mn) > IE1(Cr)** and **IE2(Cr) > IE2(Mn)**. - This satisfies the condition given in the question. 5. **Check Other Pairs**: - Repeat the analysis for other pairs (if provided) to ensure they do not meet the criteria. - For example, analyze pairs like (Mn, Fe) and (Zn, Cu) similarly. 6. **Final Answer**: - The pair that satisfies the condition is (Mn, Cr).
Promotional Banner

Topper's Solved these Questions

  • THE D AND F-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assingnment(Section -B ( Objective Type Questions)(One option is correct))|12 Videos
  • THE D AND F-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assingnment(Section -C ( Objective Type Questions)(More tha one option is correct))|11 Videos
  • THE D AND F-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|15 Videos
  • Test-12

    AAKASH INSTITUTE ENGLISH|Exercise Exercise|58 Videos
  • THE P-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section-J)|16 Videos

Similar Questions

Explore conceptually related problems

IE_(2) for an element is inveriably higher than IE_(1) because

IE_(2) for an element is inveriably higher than IE_(1) because

Choose the correct pair regarding IE_(3)

The element having lowest IE_(1)

The element having lowest IE_(1)

The IE of Be is greater than that of B.

The IE_(1) of C atom is greater than that of boron (B) atom, whereas the reverse is true for IE_(2) . Explain?

First IE of 5d seties element are higher than those of 3d and 4d series elements. This is due to:

Assertion(A) : IE_(1) of C is greater than that of B . Reason (R ): Due to penetration effect the IE_(1) of C is greater than that of B

In 3d , 4d and 5d series which element is expected to have highest IE_(1) ?

AAKASH INSTITUTE ENGLISH-THE D AND F-BLOCK ELEMENTS -Assingnment(Section -A ( Objective Type Questions)(One option is correct))
  1. The trend in ionisation enthalpy of transition element is not regular ...

    Text Solution

    |

  2. The element having lowest IE(1)

    Text Solution

    |

  3. Choose the pair in which IE(1) of first element is greater than IE(1) ...

    Text Solution

    |

  4. Which of the following element does not show the variable oxidation st...

    Text Solution

    |

  5. The most common oxidation states of 3d series elements

    Text Solution

    |

  6. In 3d series , Mn shows highest oxidation state . Why ?

    Text Solution

    |

  7. With F highest stable oxidation state of Mn is

    Text Solution

    |

  8. With O highest possible oxidation state of Mn is

    Text Solution

    |

  9. Although fluorine is more electronegative than oxygen, but the ability...

    Text Solution

    |

  10. Which of the following have highest magnetic moment ?

    Text Solution

    |

  11. Reduction potential of M^(2+)//M will depend on

    Text Solution

    |

  12. Amongst the following ions, which is considered as most stable in M^(2...

    Text Solution

    |

  13. Electrode potential of M^(2+)//M for Ni is abnormal because of

    Text Solution

    |

  14. The species which is paramagnetic

    Text Solution

    |

  15. A compound of a metal ion M^(X+)(z=24) has a spin only magnetic moment...

    Text Solution

    |

  16. The species which convert Cu^(2+) to Cu^(+)

    Text Solution

    |

  17. Which of the following is not a condition for complex formation?

    Text Solution

    |

  18. Brass is an alloy of :

    Text Solution

    |

  19. In acidic medium one mole of MnO(4)^(-) accepts how many moles of elec...

    Text Solution

    |

  20. In the dichromate anion (Cr2O7^(2-))

    Text Solution

    |