With F highest stable oxidation state of Mn is

Options

A. `+6`
B. `+4`
C. `+7`
D. `+3`

Answer

To determine the highest stable oxidation state of manganese (Mn) when it is combined with fluorine (F), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Elements and Their Properties**:
- Manganese (Mn) is a transition metal with atomic number 25, and its electronic configuration is [Ar] 3d^5 4s^2.
- Fluorine (F) is a highly electronegative non-metal with atomic number 9, and its electronic configuration is 1s^2 2s^2 2p^5.

2. **Determine the Possible Oxidation States of Manganese**:
- Manganese can exhibit multiple oxidation states ranging from +2 to +7 due to its ability to lose different numbers of electrons from its 4s and 3d orbitals.

3. **Consider the Oxidation State of Fluorine**:
- Fluorine typically has an oxidation state of -1 because it is highly electronegative and readily accepts one electron.

4. **Formulate the Compound**:
- The highest oxidation state of manganese when combined with fluorine can be analyzed through the formation of manganese fluoride compounds. The highest stable compound formed is MnF4.

5. **Calculate the Oxidation State of Manganese in MnF4**:
- In the compound MnF4, let the oxidation state of manganese be represented as X.
- The equation for the compound can be set up as follows:
\[ X + 4(-1) = 0 \]
- Simplifying this gives:
\[ X - 4 = 0 \implies X = +4 \]

6. **Conclusion**:
- The highest stable oxidation state of manganese when combined with fluorine is +4, as seen in the compound MnF4.

### Final Answer:
The highest stable oxidation state of Mn with fluorine is **+4**.

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