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Which ion will give colour in the aqueou...

Which ion will give colour in the aqueous solution ?

A

`Ti^(3+)`

B

`Cu^(2+)`

C

`Cu^+`

D

Both a and b

Text Solution

AI Generated Solution

The correct Answer is:
To determine which ion will give color in an aqueous solution, we need to analyze the electronic configurations of the given ions: Ti³⁺, Cu²⁺, Cu⁺, and both A and B. The presence of unpaired electrons in the d-orbitals of these ions is what causes them to exhibit color. ### Step-by-Step Solution: 1. **Identify the Ions and Their Electronic Configurations**: - **Titanium (Ti)** has an atomic number of 22. Its electronic configuration is: \[ \text{Ti: } [\text{Ar}] 3d^2 4s^2 \] - **Copper (Cu)** has an atomic number of 29. Its electronic configuration is: \[ \text{Cu: } [\text{Ar}] 3d^{10} 4s^1 \] 2. **Determine the Configuration of Ti³⁺**: - For Ti³⁺, we remove three electrons: - First, remove the two electrons from the 4s orbital. - Then, remove one electron from the 3d orbital. - The electronic configuration for Ti³⁺ becomes: \[ \text{Ti}^{3+}: [\text{Ar}] 3d^1 4s^0 \] - **Unpaired Electrons**: There is **1 unpaired electron** in Ti³⁺. 3. **Determine the Configuration of Cu²⁺**: - For Cu²⁺, we remove two electrons: - One from the 4s orbital and one from the 3d orbital. - The electronic configuration for Cu²⁺ becomes: \[ \text{Cu}^{2+}: [\text{Ar}] 3d^9 4s^0 \] - **Unpaired Electrons**: There is **1 unpaired electron** in Cu²⁺. 4. **Determine the Configuration of Cu⁺**: - For Cu⁺, we remove one electron from the 4s orbital: - The electronic configuration for Cu⁺ becomes: \[ \text{Cu}^+: [\text{Ar}] 3d^{10} 4s^0 \] - **Unpaired Electrons**: There are **no unpaired electrons** in Cu⁺. 5. **Conclusion**: - Ions that exhibit color in aqueous solutions must have unpaired electrons. - From our analysis: - Ti³⁺ has 1 unpaired electron (shows color). - Cu²⁺ has 1 unpaired electron (shows color). - Cu⁺ has no unpaired electrons (does not show color). - Therefore, the ions that give color in aqueous solution are **Ti³⁺ and Cu²⁺**. ### Final Answer: The correct option is **both A (Ti³⁺) and B (Cu²⁺)** show color in aqueous solution. ---
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