Glycerylester of Stearic acid + NaOH `to` Sodium stearate + 'A'
Product 'A' in the above reaction is

Options

A. Acetone
B. Glycol
C. Methanol
D. Glycerol

Answer

To determine the product 'A' in the reaction between glyceryl ester of stearic acid and NaOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is the glyceryl ester of stearic acid. The structure can be represented as:
\[ \text{C}_{3}\text{H}_{5}(\text{OOC-C}_{17}\text{H}_{35})_{3} \]
- This indicates a triglyceride formed from glycerol and three molecules of stearic acid.

2. **Reaction with NaOH**:
- When the glyceryl ester of stearic acid reacts with sodium hydroxide (NaOH), a process called saponification occurs. This reaction breaks the ester bonds, resulting in the formation of soap and glycerol.
- The balanced reaction can be represented as:
\[ \text{C}_{3}\text{H}_{5}(\text{OOC-C}_{17}\text{H}_{35})_{3} + 3 \text{NaOH} \rightarrow 3 \text{C}_{17}\text{H}_{35}\text{COONa} + \text{A} \]

3. **Identify the Products**:
- The products of this reaction are sodium stearate (the soap) and product 'A'.
- Sodium stearate is represented as:
\[ \text{C}_{17}\text{H}_{35}\text{COONa} \]
- The other product, 'A', is the by-product formed during the saponification process.

4. **Determine Product 'A'**:
- The by-product 'A' is glycerol, which is formed when the ester bonds are broken. The structure of glycerol is:
\[ \text{C}_{3}\text{H}_{8}\text{O}_{3} \text{ or } \text{CH}_{2}\text{(OH)-CHOH-CH}_{2}\text{(OH)} \]

5. **Conclusion**:
- Therefore, product 'A' in the reaction is glycerol.

### Final Answer:
Product 'A' is **glycerol**.

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