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A tall true breeding garden pea plant is...

A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the `F_(1)` plant were selfed the resulting genotypeswere in the ratio of

A

`3:1::"Dwarf":"Tall"`

B

`1:2:1::"Tall homozygous" : "Tall homozygous":"Dwarf"`

C

`1:2:1::"Tall heterozygous" : "Tall homozygous" : "Dwarf"`

D

`3:1: : "Tall" : "Dwarf"`

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AI Generated Solution

The correct Answer is:
To solve the question regarding the cross between a tall true breeding garden pea plant and a dwarf true breeding garden pea plant, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Parent Genotypes**: - The tall true breeding plant is homozygous dominant, represented as **TT**. - The dwarf true breeding plant is homozygous recessive, represented as **tt**. 2. **Determine the Gametes**: - The tall plant (TT) can only produce gametes with the allele **T**. - The dwarf plant (tt) can only produce gametes with the allele **t**. 3. **F1 Generation**: - When the tall (TT) and dwarf (tt) plants are crossed, all offspring in the F1 generation will be heterozygous **Tt**. - Therefore, the genotype of the F1 plants is **Tt** (all tall). 4. **Selfing the F1 Generation**: - When the F1 plants (Tt) are selfed, we perform a cross between two heterozygous plants (Tt x Tt). 5. **Construct a Punnett Square**: - Create a Punnett square to visualize the possible genotypes of the offspring: ``` T | t --------------- T | TT | Tt --------------- t | Tt | tt ``` - The resulting genotypes from the Punnett square are: - **TT** (1) - **Tt** (2) - **tt** (1) 6. **Calculate the Genotypic Ratio**: - The genotypic ratio of the offspring is: - 1 TT : 2 Tt : 1 tt - Therefore, the genotypic ratio is **1:2:1**. 7. **Identify the Phenotypes**: - The phenotypes corresponding to the genotypes are: - **TT** and **Tt** both express the tall phenotype. - **tt** expresses the dwarf phenotype. - The phenotypic ratio is: - 3 tall (TT and Tt) : 1 dwarf (tt) - Therefore, the phenotypic ratio is **3:1**. 8. **Conclusion**: - The resulting genotypes from selfing the F1 plants are in the ratio of **1:2:1**. ### Final Answer: The resulting genotypes from the selfing of F1 plants are in the ratio of **1:2:1**.
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