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A colour blind man marries a woman with ...

A colour blind man marries a woman with normal sight who has no history of colour blindness in her family.What is the probablity of their grandson being colour blind ?

A

0.25

B

0.5

C

1

D

Nil

Text Solution

AI Generated Solution

The correct Answer is:
To determine the probability of the grandson being color blind, we need to analyze the genetic inheritance of color blindness, which is a sex-linked recessive trait. Here’s a step-by-step solution: ### Step 1: Identify the Genotypes - A color-blind man has the genotype X^cY (where X^c represents the X chromosome with the color blindness allele). - The woman with normal sight, who has no history of color blindness in her family, is likely to have the genotype XX (homozygous normal). ### Step 2: Determine the Offspring's Genotypes When the color-blind man (X^cY) marries the normal sight woman (XX), we can set up a Punnett square to determine the possible genotypes of their children. | | X | X | |-------|-----|-----| | X^c | X^cX | X^cX | | Y | XY | XY | From the Punnett square, we can see the possible offspring: - 50% (X^cX) - Female carriers of color blindness (normal sight) - 50% (XY) - Normal sight males ### Step 3: Identify the Next Generation The next generation consists of: - 2 daughters (carriers, X^cX) - 2 sons (normal sight, XY) ### Step 4: Analyze the Grandson's Probability Now, we need to consider the potential mating of these offspring. The only way for a grandson to be color blind is if one of the daughters (carriers) has children with a normal sight male (XY). #### Possible Cross: - Carrier female (X^cX) with a normal male (XY): | | X | Y | |-------|-----|-----| | X^c | X^cX | X^cY | | X | XX | XY | From this cross, the possible offspring are: - 50% (X^cX) - Female carriers (normal sight) - 25% (XX) - Normal sight females - 25% (X^cY) - Color blind males ### Step 5: Calculate the Probability of a Color Blind Grandson - Out of the possible offspring from the carrier female and normal male, there is a 25% chance that a male child (grandson) will be color blind (X^cY). ### Conclusion Thus, the probability of their grandson being color blind is **0.25** or **25%**.
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