In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is

Options

A. 1. `0.4`
B. 2. `0.5`
C. 3. `0.6`
D. 6. `0.7`

Answer

To calculate the frequency of allele A in the given population, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotype Counts**:
- Genotype AA: 360 individuals
- Genotype Aa: 480 individuals
- Genotype aa: 160 individuals

2. **Calculate Total Individuals**:
- Total individuals in the population = 1000

3. **Calculate the Frequency of Each Genotype**:
- Frequency of AA (p²) = Number of AA individuals / Total individuals
\[ p^2 = \frac{360}{1000} = 0.36 \]
- Frequency of Aa (2pq) = Number of Aa individuals / Total individuals
\[ 2pq = \frac{480}{1000} = 0.48 \]
- Frequency of aa (q²) = Number of aa individuals / Total individuals
\[ q^2 = \frac{160}{1000} = 0.16 \]

4. **Calculate the Frequency of Allele A (p)**:
- Since p² is the frequency of the homozygous dominant genotype (AA), we can find p by taking the square root of p²:
\[ p = \sqrt{p^2} = \sqrt{0.36} = 0.6 \]

5. **Conclusion**:
- The frequency of allele A in the population is 0.6.

### Final Answer:
The frequency of allele A in the population is **0.6**.

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