How many different kinds of gametes will be produced by a plant having the genotype AABbCC ?

Options

A. Three
B. Four
C. Nine
D. Two

Answer

To determine how many different kinds of gametes will be produced by a plant with the genotype AABbCC, we can follow these steps:

### Step 1: Identify the alleles for each gene
The genotype AABbCC consists of three genes:
- Gene 1: A (homozygous dominant, AA)
- Gene 2: B (heterozygous, Bb)
- Gene 3: C (homozygous dominant, CC)

### Step 2: Determine the possible alleles for each gene
- For Gene 1 (A): Since it is homozygous (AA), it can only contribute the allele A.
- For Gene 2 (B): Since it is heterozygous (Bb), it can contribute either allele B or b.
- For Gene 3 (C): Since it is homozygous (CC), it can only contribute the allele C.

### Step 3: Calculate the combinations of alleles
To find the total number of different gametes, we multiply the number of options for each gene:
- For Gene 1 (A): 1 option (A)
- For Gene 2 (B): 2 options (B or b)
- For Gene 3 (C): 1 option (C)

So, the total number of different gametes = Number of options for Gene 1 × Number of options for Gene 2 × Number of options for Gene 3
= 1 × 2 × 1 = 2

### Step 4: List the possible gametes
The possible gametes produced by the genotype AABbCC are:
1. ABC (from A, B, C)
2. AbC (from A, b, C)

### Conclusion
Thus, the plant with the genotype AABbCC will produce **2 different kinds of gametes**.