Haemophilic man marries a normal woman. Their offspring will be

Options

A. All haemophiic
B. All boys haemophilic
C. All girls haemophilic
D. All normal

Answer

To solve the question regarding the offspring of a hemophilic man and a normal woman, we can follow these steps:

### Step 1: Understand Hemophilia
Hemophilia is an inherited genetic disorder that affects the blood's ability to clot. It is primarily an X-linked recessive disorder, meaning that the gene responsible for hemophilia is located on the X chromosome.

### Step 2: Determine the Genotypes
- A hemophilic man has the genotype **XhY** (where Xh represents the X chromosome with the hemophilia allele).
- A normal woman can have two possible genotypes: either **XX** (homozygous normal) or **XhX** (heterozygous carrier). For this scenario, we will consider the normal woman as **XX**.

### Step 3: Set Up a Punnett Square
To find the possible offspring, we can set up a Punnett square using the genotypes of the parents:
- The father (hemophilic man) can pass on either **Xh** or **Y**.
- The mother (normal woman) can pass on either **X**.

The combinations would be:
- From father: Xh (hemophilic) or Y (normal male)
- From mother: X (normal)

### Step 4: Analyze the Offspring
The possible combinations from the Punnett square are:
1. Xh (from father) and X (from mother) → **XhX** (carrier girl)
2. Y (from father) and X (from mother) → **XY** (normal boy)

### Step 5: Conclusion
The offspring of a hemophilic man and a normal woman will be:
- Carrier girls (XhX)
- Normal boys (XY)

Thus, all the offspring will either be carrier girls or normal boys, but none will be hemophilic.

### Final Answer
The correct option is: **All normal** (meaning the boys are normal and the girls are carriers).

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