Home
Class 12
CHEMISTRY
Copper oxide was prepared by two differe...

Copper oxide was prepared by two different methods. In case, 1.75 g of the metal gave 2. 19 g of oxide. In the second case, 1.14 g of the metal gave 1.43 g of the oxide, show that the given data illustrate the law of constant proportions.

Text Solution

AI Generated Solution

To demonstrate that the given data illustrates the law of constant proportions, we will analyze the mass ratios of copper and oxygen in both cases. ### Step-by-Step Solution: **Step 1: Calculate the mass of oxygen in Case 1.** - Given: - Mass of copper (Cu) = 1.75 g - Mass of copper oxide (CuO) = 2.19 g ...
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise TRY YOURSELF|60 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION A (Objective Type Questions (One option is correct))|46 Videos
  • SOME BASIC CONCEPT OF CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT( SECTION - D) Assertion-Reason Type Questions|15 Videos
  • STATES OF MATTER

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION-D)|14 Videos

Similar Questions

Explore conceptually related problems

1.80g of a certain metal burnt in oxygen gave 3.0g of its oxide 1.50g of the same metal heated in steam gave 2.50g of its oxide. Show that these illustrate the law of constant proportion .

1.0 g of a metal oxide gave 0.2 g of metal. Calculate the equivalent weight of the metal.

The common salt was obtained from two different sources. In one sample, the percentage of chlorine was found to be 60.75 %. In the second sample, 3.888 g of chlorine were present in 6.4 g of the salt. Show that these data are in accordance to the law of constant proportion.

Element X and Y form two different compounds. In the first compound, 0.324 g X is combined with 0.471 g Y . In the second compound, 0.117 g X is combined with 0.509 g Y . Show that these data illusttate the law of multiple proportions.

Element X and Y form two different compounds. In the first compound, 0.324 g X is combined with 0.471 g Y . In the second compound, 0.117 g X is combined with 0.509 g Y . Show that these data illusttate the law of multiple proportions.

In an experiment, 2.4 g of Iron oxide on reduction with Hydrogen yields 1.68 g of Iron. In another experiment, 2.9 g of Iron oxide give 2.03 g of Iron on reduction with Hydrogen. Show that the above data illustrates the law of constant proportion.

4 g of a metal oxide contains 1.6 g-oxygen, then equivalent mass of the metal is

metal combines with oxygen to form two oxides, having the following composition: (i) 0.398 g of the first metal oxide contains 0.318g of metal. (ii) 0.716 g of the second oxide contains 0.636g of the metal. Show that the above data agrees with the law of multiple proportions.

A metal forms two oxides. The higher oxide contains 80% metal. 0.72 g of the lower oxide gave 0.8 g of higher oxide when oxidised. Calculate the weight of oxygen the combines with the fixed weight of metal in the two oxides, and show that the data supports the law of multiple proportines

1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is